(i) determine the deformation of segment (2). (ii) determine the deflection of joint D with respect to the fixed support at A. (iii) calculate the maximum normal stress in the entire axial member.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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1- A solid axial member which is made from three parts with different materials (sections 1,2,
and 3) is loaded and supported as shown in the Figure 1. Segments (1) has a diameter of 30 mm,
segment (2) has a diameter of 20 mm and segment (3) has a diameter of 25 mm. For the Elastic
modulus of segments please follow the table 1.
Surname starting (A-M)
Surname starting (N-Z)
1.1 m
1.3 m
0.7 m
B.
(1)
E₁ = 200 GPa
E₁ = 100 GPa
(2)
(3)
P₁ = 40 kN
P₂ = 10 KN
P3 = 20 kN
Figure 1
Table 1
E₂ = 100 GPa
E₂ = = 80 GPa
E3 = 80 GPa
E3 = 200 GPa
(i) determine the deformation of segment (2).
(ii) determine the deflection of joint D with respect to the fixed support at A.
(iii) calculate the maximum normal stress in the entire axial member.
(iv) What type of changes the design do you suggest to reduce the deflection on joint D
calculated in section (ii). Explain your answer.
Transcribed Image Text:1- A solid axial member which is made from three parts with different materials (sections 1,2, and 3) is loaded and supported as shown in the Figure 1. Segments (1) has a diameter of 30 mm, segment (2) has a diameter of 20 mm and segment (3) has a diameter of 25 mm. For the Elastic modulus of segments please follow the table 1. Surname starting (A-M) Surname starting (N-Z) 1.1 m 1.3 m 0.7 m B. (1) E₁ = 200 GPa E₁ = 100 GPa (2) (3) P₁ = 40 kN P₂ = 10 KN P3 = 20 kN Figure 1 Table 1 E₂ = 100 GPa E₂ = = 80 GPa E3 = 80 GPa E3 = 200 GPa (i) determine the deformation of segment (2). (ii) determine the deflection of joint D with respect to the fixed support at A. (iii) calculate the maximum normal stress in the entire axial member. (iv) What type of changes the design do you suggest to reduce the deflection on joint D calculated in section (ii). Explain your answer.
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