Reaction Engineering The first order, reversible reaction A ↔ B + 2C is taking place in a membrane reactor. Pure A enters the reactor, and B diffuses through the membrane. Unfortunately, some of reactant A also diffuses through the membrane. Other information of the reaction in the membrane reactor is shown in the image attached. Please formulate the differential equations that can be used to solve for the flow rates of species A, B, and C as a function of reactor volume and the flow rates of A and B through the membrane
Reaction Engineering The first order, reversible reaction A ↔ B + 2C is taking place in a membrane reactor. Pure A enters the reactor, and B diffuses through the membrane. Unfortunately, some of reactant A also diffuses through the membrane. Other information of the reaction in the membrane reactor is shown in the image attached. Please formulate the differential equations that can be used to solve for the flow rates of species A, B, and C as a function of reactor volume and the flow rates of A and B through the membrane
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
The first order, reversible reaction
A ↔ B + 2C
is taking place in a membrane reactor. Pure A enters the reactor, and B diffuses through the
membrane. Unfortunately, some of reactant A also diffuses through the membrane. Other
information of the reaction in the membrane reactor is shown in the image attached.
Please formulate the differential equations that can be used to solve for the flow rates of
species A, B, and C as a function of reactor volume and the flow rates of A and B through
the membrane

Transcribed Image Text:k = 10 min¹
Kc = 0.01 mol/dm
kCA = 1 min¹
KCB = 40 min-¹
FAO 100 mol/min
16= 100 dm³/min
Vreactor = 20 dm³
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