RelerenceaFor rubidium, the enthalpy of vaporization is 75.82 kJ/mol and the entropy of vaporization is 110.1 J/K•mol. What is the normal boiling point ofrubidium?KNormal boiling point =10 item attempts remainingTry Another VersionSubmit AnswerVisitedrch32°FF3F4FSF6F7F9F10F11F12B/OPRTSCINSERT2347.EA\YPIF\GCIVM.. ..IN00LI

Given, ΔH = 75.82 kJ/mol = 75820 J/mol ΔS = 110.1 J/K.mol ΔG = ΔH - TΔS Since boiling is an equilibrium process, liquid and water vapour co exist. Thus, ΔG will be zero. ΔH - TΔS = 0 ΔH = TΔS T = ΔH/ΔS = 75820 J/mol / 110.1 J/K. mol = 688.6 K Thus, the normal boiling point is 688.6 K

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[Re For rubidium, the enthalpy of vaporization is 75.82 kJ/mol and the entropy of vaporization is 110.1 J/K•mol. What is the normal boiling point of rubidium? Normal boiling point = K Submit Answer Try Another Version 10 item attempts remaining

[Re For rubidium, the enthalpy of vaporization is 75.82 kJ/mol and the entropy of vaporization is 110.1 J/K•mol. What is the normal boiling point of rubidium? Normal boiling point = K Submit Answer Try Another Version 10 item attempts remaining

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Relerencea
For rubidium, the enthalpy of vaporization is 75.82 kJ/mol and the entropy of vaporization is 110.1 J/K•mol. What is the normal boiling point of
rubidium?
K
Normal boiling point =
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