For the titration of 25.0 mL of 0.125 M acetic acid (CH3COOH, K₂ = 1.8x10-5) with 0.125 M NaOH, what volume of NaOH is needed toreach the equivalence point?O 12.5 mLO 25.0 mLO 15.00 mLO 30.00 mLCH3COOH(aq) + NaOH(aq) →→→ NaCH3COO(aq) + H₂O(l)

Molarity is defined as number of mole of solute divide by volume of solution in liter

Answered: ration of 25.0 mL of 0.125 M acetic…

ration of 25.0 mL of 0.125 M acetic acid (CH3COOH, K₂ = 1.8x105) with 0.125 M NaOH, what volume of NaOH is needed to equivalence point? L L CH3COOH(aq) + NaOH(aq) →→→ NaCH3COO(aq) + H₂O(l)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

For the titration of 25.0 mL of 0.125 M acetic acid (CH3COOH, K₂ = 1.8x10-5) with 0.125 M NaOH, what volume of NaOH is needed to
reach the equivalence point?
O 12.5 mL
O 25.0 mL
O 15.00 mL
O 30.00 mL
CH3COOH(aq) + NaOH(aq) →→→ NaCH3COO(aq) + H₂O(l)

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