Rate Law from Concentration versus Time Data NO2(9) + CO(g) NO(g) + CO2(g) The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C. At a temperature below 225°C the following data were obtained: [NO2] (mol/L) Time (s) 0.560 5.00x102 0.547 1.25x103 0.528 1.88x103 0.513
Rate Law from Concentration versus Time Data NO2(9) + CO(g) NO(g) + CO2(g) The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C. At a temperature below 225°C the following data were obtained: [NO2] (mol/L) Time (s) 0.560 5.00x102 0.547 1.25x103 0.528 1.88x103 0.513
Chemistry
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![Rate Law from Concentration versus Time Data
NO2(9) + CO(g) NO(g) + CO2(g)
The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C.
At a temperature below 225°C the following data were obtained:
[NO2]
(mol/L)
Time
(s)
0.560
5.00x102 0.547
1.25x103 0.528
1.88x103 0.513
3.75x103 0.473
7.50x103 0.409
Which of the following expressions for the rate law (either differential or integrated) are completely consistent with the above experimental data.
v d[NO]/dt = k[NO2]?
v In[NO2] - In[NO2lo = -kt
v K[CO][NO2] = -d[CO]/dt
v 1/[NO2] = kt + 1/[NO2]o
v -d[NO2]/dt = k[NO2]2
提交答案| Tries 0/5
Calculate the rate constant (k).
Enter the numerical value and corresponding Units.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcce97c76-5df7-4b59-824d-2e8a30ab4db6%2F3f45aaaa-7be6-4840-9f8a-e789eccd9733%2Fa807qsd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Rate Law from Concentration versus Time Data
NO2(9) + CO(g) NO(g) + CO2(g)
The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C.
At a temperature below 225°C the following data were obtained:
[NO2]
(mol/L)
Time
(s)
0.560
5.00x102 0.547
1.25x103 0.528
1.88x103 0.513
3.75x103 0.473
7.50x103 0.409
Which of the following expressions for the rate law (either differential or integrated) are completely consistent with the above experimental data.
v d[NO]/dt = k[NO2]?
v In[NO2] - In[NO2lo = -kt
v K[CO][NO2] = -d[CO]/dt
v 1/[NO2] = kt + 1/[NO2]o
v -d[NO2]/dt = k[NO2]2
提交答案| Tries 0/5
Calculate the rate constant (k).
Enter the numerical value and corresponding Units.
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