RANK(t, x) rank = 0 while (t#x) if (t.key < x.key) if t.left # NIL rank += t.left.size rank++ t = t.right else t = t.left if t.left != NIL rank += t.left.size rank++ Return rank Your job is to update this algorithm so that it takes as input a value k which is comparable to the keys in the tree. The new version should return the number of elements in the tree whose key values are less than or equal to k. Note that the value k itself may or may not exist in the tree. Call your new algorithm BST-LessthanK(T, k) and justify that the runtime is still O(h), where h is the height of the tree.

RANK(t, x) rank = 0 while (t#x) if (t.key < x.key) if t.left # NIL rank += t.left.size rank++ t = t.right else t = t.left if t.left != NIL rank += t.left.size rank++ Return rank Your job is to update this algorithm so that it takes as input a value k which is comparable to the keys in the tree. The new version should return the number of elements in the tree whose key values are less than or equal to k. Note that the value k itself may or may not exist in the tree. Call your new algorithm BST-LessthanK(T, k) and justify that the runtime is still O(h), where h is the height of the tree.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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