Rank the following compounds in order of decreasing boiling point: sodium bromide (NaBr), methane (CH4), and formaldehyde (CH,O) Rank from highest to lowest boiling point. To rank items as equivalent, overlap them. > View Available Hint(s) Reset Help formaldehyde ( CH20 sodium bromide (NaBr ) methane ( CH,) Lowest boiling point
Rank the following compounds in order of decreasing boiling point: sodium bromide (NaBr), methane (CH4), and formaldehyde (CH,O) Rank from highest to lowest boiling point. To rank items as equivalent, overlap them. > View Available Hint(s) Reset Help formaldehyde ( CH20 sodium bromide (NaBr ) methane ( CH,) Lowest boiling point
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Part B
Rank the following compounds in order of decreasing boiling point: sodium bromide (NaBr), methane (CH,), and formaldehyde (CH,O)
Rank from highest to lowest boiling point. To rank items as equivalent, overlap them.
> View Available Hint(s)
Reset
Help
formaldehyde ( CH2O
sodium bromide (NaBr
methane ( CH,)
Highest boiling point
Lowest boiling point
O The correct ranking cannot be determined.
B.
%23
W Word
P Type here to search

Transcribed Image Text:Activity 7
ntermolecular Forces in Liquids
4 of 6
Applying intermolecular forces to properties
A dipole moment tends to stabilize the liquid state of the compound as molecules align to form attractive molecular interactions. A liquid state that is more stable, that is one that is held together by stronger dipole forces, will have a higher boiling point
since it takes more energy to break these intermolecular forces.
Part B
i decreasing boiling point: sodium bromide (NaBr), methane (CH,), and formaldehyde (CH2O)
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