random survey of 419 people, 292 indicated that they prefered to go a forest to winter camp. Find a 90% confidence interval for the true proportion of all people who prefer to go to a forest to winter camp. (Round answers to three decimal places.) Error = < p < %3D
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- A random sample of 100 employees at a company shows that 62 are female. Form a 90% confidence interval for the proportion of all employees who are female. The interval is 0.62 what margin of error? Round your answer to 3 decimal places.Fron a random sample of 500 Google play apps with more than 1 million installs, 498 are free. Find and interpret a 95% confidence interval for the population proportion of free apps with more than 1 million installs. Write your interval up to 4 decimal places.number 28 The following data shows the price of a certain stock over the last 8 months. Month Price 1 2.10 2 1.98 3 2.01 4 1.89 5 1.90 6 1.89 7 1.72 8 1.65 (a) Develop a scatter diagram and draw a trend line through the points. A graph has a horizontal axis labeled "Month" with values from 0 to 10 and a vertical axis labeled "Price" with values from 0 to 2.5. The scatter diagram has 8 points. A line goes through the center of the pattern of points. A pattern goes down and right becoming more steep from (1, 1.7) to (8, 1.25). A graph has a horizontal axis labeled "Month" with values from 0 to 10 and a vertical axis labeled "Price" with values from 0 to 2.5. The scatter diagram has 8 points. A line goes through the center of the pattern of points. A pattern goes down and right from (1, 2.1) to (8, 1.65). A graph has a horizontal axis labeled "Month" with values from 0 to 10 and a vertical axis labeled "Price" with values from 0 to 2.5. The scatter…
- A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?Out of 400 people sampled, 368 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to four places< p <Researchers are studying whether the proportion of homeschooled children in district 1 (considered 1) is less than the proportion of homeschooled children in neighboring district 2 (considered as 2). To test the theory info was gathered: district 1 had 600 students of which 90 were homeschooled. District 2 had 550 students of which 99 were homeschooled. What is the 95% confidence interval for the difference proportion between district 1 and 2? A. (-0.086, 0.026) B. (0.143, 0.217) C. (0.113, 0.187)
- In a random sample of 296 people, 179 said that they watched educational television. Find the upper bound limit of the 95% confidence interval of the true proportion of people who watched educational television. Round your answer to 3 decimal places.Out of 300 people sampled, 219 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places.A random sample of 75 customers was polled. .626 and the 95% confidence intervalIn a sample of 300 adults, 198 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places RectanIn a sample of 360 adults, 266 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesIn a sample of 510 adults, 281 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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