Rampless Unimeleculo gras a Eimaon - Bee 1) A chemical reaction proceeds with the proposed reaction mechanism below; Step Kinetics Assignment SCH4U0 E (kJ/mol) 754H +175 25-AH Ne) +Oze) → N;0 +O«). +50 1 N20 +Oe → NOe + NO«) -150+AH +25 3. NO +O + N0e) a) Draw the potential energy diagram for this reaction below. 300 250 P. Е. 200 (k J/ 150 mo 1) 100 Nte +0, 2(g) 50 b) What is the overall reaction? Nzg) + 2 0xg -> c) Which step is the rate determining step? Explain why. step 2 because it has the highest activation energy. d) What would be the rate law for this reaction? K= [ e) Explain what would happen to the rate if the concentration of Ne doubled. f) Use a dotted line to show what would happen if a catalyst was added to the reaction. g) Identify the spot on the graph that represents the transition state for reaction 2. Lono produced and

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Chapter1: Chemical Foundations
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Unimeleculo
gras a
Teact
Eimaan
e
- Rea
1) A chemical reaction proceeds with the proposed reaction mechanism below;
Step
Kinetics Assignment
SCH4U0
E (kJ/mol)
75AH
+175
25-AH
+50
N2e) + Oze) → N,O« +O«).
1
+25
-150+0H
N2O +Oz«) → NOe) +NO)
NOw +O«) → N0ze)
a) Draw the potential energy diagram for this reaction below.
300
250
P.
E.
200
(k
J/
150
mo
1)
100
+0218)
50
b) What is the overall reaction?
N2 9) + 2 Ozcg
->
c) Which step is the rate determining step? Explain why.
Step 2 because it has the highest activation energy.
d) What would be the rate law for this reaction?
K= [
e) Explain what would happen to the rate if the concentration of Ne
doubled.
f) Use a dotted line to show what would happen if a catalyst was added to the reaction.
g) Identify the spot on the graph that represents the transition state for reaction 2.
h) Identify the intermediates present in this reaction. (Intermediates are produced and
consumed in the reaction mechanisms)
Transcribed Image Text:amples: Unimeleculo gras a Teact Eimaan e - Rea 1) A chemical reaction proceeds with the proposed reaction mechanism below; Step Kinetics Assignment SCH4U0 E (kJ/mol) 75AH +175 25-AH +50 N2e) + Oze) → N,O« +O«). 1 +25 -150+0H N2O +Oz«) → NOe) +NO) NOw +O«) → N0ze) a) Draw the potential energy diagram for this reaction below. 300 250 P. E. 200 (k J/ 150 mo 1) 100 +0218) 50 b) What is the overall reaction? N2 9) + 2 Ozcg -> c) Which step is the rate determining step? Explain why. Step 2 because it has the highest activation energy. d) What would be the rate law for this reaction? K= [ e) Explain what would happen to the rate if the concentration of Ne doubled. f) Use a dotted line to show what would happen if a catalyst was added to the reaction. g) Identify the spot on the graph that represents the transition state for reaction 2. h) Identify the intermediates present in this reaction. (Intermediates are produced and consumed in the reaction mechanisms)
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