рабоватP= 1.5 bar=SRankine cycle 1-2-3-4-1Fluid is steamState/1234P (bar)601.51.560h(kJ/kg)27842314467.3475.4X v (m³/kg)10.8300.001053T-3 diagram includes irreversibilities in adiabatic expansionandcompression processes.Cycle operates with steady flow devices between 60 bar $1.5 bar.To300 к1 barPo =Ask1) % iSENTROPIC TURBINE EFFICIENCY2) RATE OF EXERGY DESTRUCTION PER UNITFLOWING IN TURBINE IN (J/kg)3) % ISENTROPIC PUMP EFFICIENCY4) % THERMAL EFFICIENCY3 (kJ/kg. K)S5.8886.2MASS OF STEAM

Given-Information:- p = 60 barp = 1.5 barT0 = 300 Kp0 = 1 bar To-Determine:- a. % isentropic turbine…

Answered: рабоваг P= lo5 bar 1.5

Engineering

Mechanical Engineering

рабоваг P= lo5 bar 1.5

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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