R3 II R2 RI R5
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter7: Parallel Circuits
Section: Chapter Questions
Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....
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answe the last 2 questions please
![For R1=7, R2=50, R3=12, R4=15, RS=9 and I1=1.1 A in the shown figure, use current divider to calculate the following
R3
R4 V.
II
R2
R5
VO =
7.103
JO =
0.079
the power dissipated R1=
2114
the power dissipated R2=
02957
the power dissipated R3=
4.71
the power dissipated R4=
3.364](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb7f8fc7-9a10-4a0c-b7df-1c8d012e6946%2Fc5155acb-846f-4cef-8d0a-12525ea0be10%2Fltny3w_processed.png&w=3840&q=75)
Transcribed Image Text:For R1=7, R2=50, R3=12, R4=15, RS=9 and I1=1.1 A in the shown figure, use current divider to calculate the following
R3
R4 V.
II
R2
R5
VO =
7.103
JO =
0.079
the power dissipated R1=
2114
the power dissipated R2=
02957
the power dissipated R3=
4.71
the power dissipated R4=
3.364
![the power dissipated R5=
the power developed by the current source=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb7f8fc7-9a10-4a0c-b7df-1c8d012e6946%2Fc5155acb-846f-4cef-8d0a-12525ea0be10%2Ftaalda_processed.png&w=3840&q=75)
Transcribed Image Text:the power dissipated R5=
the power developed by the current source=
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