r1/7 Consider the definite integral " z sin (7=) dx The first step in evaluating this integral is to apply integration by parts: u dv = uv - v du where u = arcsin(x) and du = h(r) dz where h(z) = 1 Note: Use arcsin(z) for sin (2). 1/7 v du = r1/7 After integrating by parts, we obtain the integral I f(z) dz on the right hand side where f(1) = 7(x*2)/2sqrt(1-49(x**2)) The most appropriate substitution to simplify this integral is z = g(t) where g(t) = sin(t)7 Note: We are using t as variable for angles instead of 0, since there is no standard way to type e on a computer keyboard. After making this substitution and simplifying (using trig identities), we obtain the integral k(t) dt where k(t) = a = b = After evaluating this integral and plugging back into the integration by parts formula we obtain: 1/7 I sin (7z) dr =

r1/7 Consider the definite integral " z sin (7=) dx The first step in evaluating this integral is to apply integration by parts: u dv = uv - v du where u = arcsin(x) and du = h(r) dz where h(z) = 1 Note: Use arcsin(z) for sin (2). 1/7 v du = r1/7 After integrating by parts, we obtain the integral I f(z) dz on the right hand side where f(1) = 7(x*2)/2sqrt(1-49(x**2)) The most appropriate substitution to simplify this integral is z = g(t) where g(t) = sin(t)7 Note: We are using t as variable for angles instead of 0, since there is no standard way to type e on a computer keyboard. After making this substitution and simplifying (using trig identities), we obtain the integral k(t) dt where k(t) = a = b = After evaluating this integral and plugging back into the integration by parts formula we obtain: 1/7 I sin (7z) dr =

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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