Let Z = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows: R = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (2, 2), (3, 0), (3, 3)}, S= {(0, 0), (0, 2), (0, 3), (2, 3)}, T = {(0, 1), (2, 3)}. S has properties Seç. R has properties Seç. symmetric, but neither reflexive nor transitive T has ... properties S transitive, symmetric but not reflexive reflexive, but neither symmetric nor transitive The equivalance relation is: R reflexive, symmetric but not transitive

Let Z = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows: R = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (2, 2), (3, 0), (3, 3)}, S= {(0, 0), (0, 2), (0, 3), (2, 3)}, T = {(0, 1), (2, 3)}. S has properties Seç. R has properties Seç. symmetric, but neither reflexive nor transitive T has ... properties S transitive, symmetric but not reflexive reflexive, but neither symmetric nor transitive The equivalance relation is: R reflexive, symmetric but not transitive

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter6: Linear Transformations

Section6.CR: Review Exercises

Problem 65CR

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Question

Let Z = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows:
R = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (2, 2), (3, 0), (3, 3)},
S= {(0, 0), (0, 2), (0, 3), (2, 3)},
T = {(0, 1), (2, 3)}.
S has
properties
Seç.
R has
properties
Seç.
symmetric, but neither reflexive nor transitive
I has ...
properties
S
transitive, symmetric but not reflexive
reflexive, but neither symmetric nor transitive
The equivalance relation is:
R
reflexive, symmetric but not transitive
reflexive, transitive but not symmetric
reflexive, symmetric and transitive
transitive, but neither symmetric nor reflexive
Sonraki sayfa

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