Let B = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows R = {(0, 1), (1,1), (2, 3),(3,3)} S= {(0, 0), (0, 2), (0, 3), (2, 3)}, T = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (1, 3),(2, 2), (3, 0), (3, 3)}, T has . properties Seç. The equivalance relation is: Seç..

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Let B = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows:
R = {(0, 1), (1,1), (2, 3),(3,3)}
S= {(0, 0), (0, 2), (0, 3), (2, 3)},
T = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (1, 3),(2, 2), (3, 0), (3, 3)},
%3D
T has . properties
Seç.
Seç.
The equivalance relation is:
R
S has . properties
transitive, symmetric but not reflexive
reflexive, symmetric but not transitive
R has . properties
reflexive, symmetric and transitive
reflexive, but neither symmetric nor transitive
reflexive, transitive but not symmetric
transitive, but neither symmetric nor reflexive
symmetric, but neither reflexive nor transitive
Transcribed Image Text:Let B = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows: R = {(0, 1), (1,1), (2, 3),(3,3)} S= {(0, 0), (0, 2), (0, 3), (2, 3)}, T = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (1, 3),(2, 2), (3, 0), (3, 3)}, %3D T has . properties Seç. Seç. The equivalance relation is: R S has . properties transitive, symmetric but not reflexive reflexive, symmetric but not transitive R has . properties reflexive, symmetric and transitive reflexive, but neither symmetric nor transitive reflexive, transitive but not symmetric transitive, but neither symmetric nor reflexive symmetric, but neither reflexive nor transitive
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