R1 Ro 2 kN Rid V id 25 kN 1 kΩ A, Vid R2 91 kM R1 10 kN Figure 11.13 Series-shunt feedback amplifier with source resistance added.

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Suppose the op amp shown has an fT of 1 MHz. What is the phase margin of the amplifier?

R1
Ro
2 kN
Rid
V id
25 kN
1 kΩ
A, Vid
R2
91 kM
R1
10 kN
Figure 11.13 Series-shunt feedback amplifier with source resistance
added.
Transcribed Image Text:R1 Ro 2 kN Rid V id 25 kN 1 kΩ A, Vid R2 91 kM R1 10 kN Figure 11.13 Series-shunt feedback amplifier with source resistance added.
Expert Solution
Step 1

Given fT = 1 MHz, 

Calculating angular frequency

ωT=2πfTωT=2π×1 MHz=2×106π Hz

Calculating transmission gain

A=ωTs+ωBωT=A0ωB

Step 2

A0ωB=2×106π Hz

Taking given value of A0

A0=80 dB

Converting value of gain decibel to normal value

A0=1080 dB20A0=104

 

 

 

Step 3

A0ωB=2×106π Hz104ωB=2×106π HzωB=2×102π rad/sec.

Given 

Rid=25 KΩRI=2 KΩRth=9.02 KΩ

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