r(0) =D ti + 3j + (를2 (를 B12 )k; (0, 3, -8/3)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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QUESTION 28

In Exercises 27–30, find the value(s) of t so that the tangent line to the
given curve contains the given point.
27. r(t) = t²i + (1 + t)j + (2t – 3)k; (-8, 2, – 1)
28. r(t) = ti + 3j +
13/2 k; (0,3,–-8/3)
29. r(t) =
2ti + t²j – t²k; (0,–4, 4)
30. r(t) = -ti + tj + (ln t)k; (2,-5,–3)
In Exercises 31-36 r(4) is the position of a particle in snace at time t
Transcribed Image Text:In Exercises 27–30, find the value(s) of t so that the tangent line to the given curve contains the given point. 27. r(t) = t²i + (1 + t)j + (2t – 3)k; (-8, 2, – 1) 28. r(t) = ti + 3j + 13/2 k; (0,3,–-8/3) 29. r(t) = 2ti + t²j – t²k; (0,–4, 4) 30. r(t) = -ti + tj + (ln t)k; (2,-5,–3) In Exercises 31-36 r(4) is the position of a particle in snace at time t
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Question no 28.

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rt=ti+3j+23t32k,0,3,-83

 

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