R: Rydberg constant. (R = 1.097x10 m). نكر و أرطامن ایکا 19 JI Example 1-1: Calculate the potential energy of an electron orbiting in gróund state for a hydrogen atóm with a kinetic energy of +13.6ev hence calculate the total energy of this electron. S les لاركرو Solution: P. E. = -9.11x10kg x (1.6x103c)* 4x (8.849X10F/M)* x (6.626x10s) -me -27.135ev. E= K.E. +P.E. = 13.6-27.135-13.6ev. check the units?

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R: Rydberg constant. (R= 1.097x10'm).
كرون أنطام انكاميم
Example 1-1: Cālculate the potential energy of an electron orbiting in ground state for a
hydrogen atóm with a kinetic energy of +13.6ev hence calculate the total energy of this
electron.
us Ues
ركترو
Solution: P. E. =
-9.11x10kg x (1.6x10c)*
4x (8.849X10F/M) x (6.626x10 *s)
-me
-27.135ev.
%3D
E K.E. +P.E.= 13.6- 27.135 -13.6ev.
check the units?
Transcribed Image Text:R: Rydberg constant. (R= 1.097x10'm). كرون أنطام انكاميم Example 1-1: Cālculate the potential energy of an electron orbiting in ground state for a hydrogen atóm with a kinetic energy of +13.6ev hence calculate the total energy of this electron. us Ues ركترو Solution: P. E. = -9.11x10kg x (1.6x10c)* 4x (8.849X10F/M) x (6.626x10 *s) -me -27.135ev. %3D E K.E. +P.E.= 13.6- 27.135 -13.6ev. check the units?
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