R, R, (a) Main switch 100A Cable 4G25 Cu Stairs I apartments 1-8 Duct 1 PEN dividing to N ond PE P= 32x10°w Cable 5G 16 Cu NF)- K50 Stairs N oportments 9-16 P= 32x10 w Duct 2 Cablel 5G16 Cu F)= K50 C25 circuit breaker Cable 4G6 Cu Electricity meter (KWn) 2 TAX + programmable clock 0-40A, 3 phases Cable 4G4 Cu Water heating system P= 9rt0w Cable SG2.5 Cu (F)= B20 Bosement ight: NEJ- B10: Cable 3G1.5 Cu P2000w Internet de nices: F= B10: Cable 3G15 Cu P<2000VW DVB-C hardware; NF)= 810, Cable 3G1.5 Cu: P<2000W Dial phone hardware, N)B10 Catle 3G1.5 Cu PC2000W ISP hardware: F)= B10 Coble JG1.5 Ce Pe2000W ISP hardware: KF)= 810; Cable 3G1.5 Cu: P<2000W Light reloy: E C1: Cable 2x0 5 Cư P<5OW Stairs Iightng: 86,Cablel 3G1 Cu: P120W Stairs il lighbng: F- 86: Cable 3GI Cu: P=120W (b) Figure 21.4 (a) Three resistors connected in parallel to a battery and the equivalent single or parallel resistance. (b) Electrical power setup in a house. (credit: Dmitry G, Wikimedia Commons) II andu arges Busbar 3-phase 12M 10mm

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Let the voltage output of the battery and resistances in the parallel connection in be the same as the previously considered series connection: V = 12.0 V , R1 = 1.00 Ω , R2 = 6.00 Ω , and R3 = 13.0 Ω .                              (a) What is the total resistance?
(b) Find the total current.                                                                                (c) Calculate the currents in each resistor, and show these add to equal the total current output of the source.
(d) Calculate the power dissipated by each resistor.                                      (e) Find the power output of the source, and show that it equals the total power dissipated by the resistors.

R,
R,
(a)
Main switch 100A
Cable 4G25 Cu
Stairs I apartments 1-8
Duct 1
PEN dividing to N ond PE
P= 32x10°w
Cable 5G 16 Cu
NF)- K50
Stairs N oportments 9-16
P= 32x10 w
Duct 2
Cablel 5G16 Cu F)= K50
C25 circuit breaker
Cable 4G6 Cu
Electricity meter (KWn)
2 TAX + programmable clock
0-40A, 3 phases
Cable 4G4 Cu
Water heating system
P= 9rt0w
Cable SG2.5 Cu (F)= B20
Bosement ight: NEJ- B10: Cable 3G1.5 Cu P2000w
Internet de nices: F= B10: Cable 3G15 Cu P<2000VW
DVB-C hardware; NF)= 810, Cable 3G1.5 Cu: P<2000W
Dial phone hardware, N)B10 Catle 3G1.5 Cu PC2000W
ISP hardware: F)= B10 Coble JG1.5 Ce Pe2000W
ISP hardware: KF)= 810; Cable 3G1.5 Cu: P<2000W
Light reloy: E C1: Cable 2x0 5 Cư P<5OW
Stairs Iightng: 86,Cablel 3G1 Cu: P120W
Stairs il lighbng: F- 86: Cable 3GI Cu: P=120W
(b)
Figure 21.4 (a) Three resistors connected in parallel to a battery and the equivalent single or parallel resistance. (b) Electrical power setup in a house.
(credit: Dmitry G, Wikimedia Commons)
II
andu arges
Busbar 3-phase 12M 10mm
Transcribed Image Text:R, R, (a) Main switch 100A Cable 4G25 Cu Stairs I apartments 1-8 Duct 1 PEN dividing to N ond PE P= 32x10°w Cable 5G 16 Cu NF)- K50 Stairs N oportments 9-16 P= 32x10 w Duct 2 Cablel 5G16 Cu F)= K50 C25 circuit breaker Cable 4G6 Cu Electricity meter (KWn) 2 TAX + programmable clock 0-40A, 3 phases Cable 4G4 Cu Water heating system P= 9rt0w Cable SG2.5 Cu (F)= B20 Bosement ight: NEJ- B10: Cable 3G1.5 Cu P2000w Internet de nices: F= B10: Cable 3G15 Cu P<2000VW DVB-C hardware; NF)= 810, Cable 3G1.5 Cu: P<2000W Dial phone hardware, N)B10 Catle 3G1.5 Cu PC2000W ISP hardware: F)= B10 Coble JG1.5 Ce Pe2000W ISP hardware: KF)= 810; Cable 3G1.5 Cu: P<2000W Light reloy: E C1: Cable 2x0 5 Cư P<5OW Stairs Iightng: 86,Cablel 3G1 Cu: P120W Stairs il lighbng: F- 86: Cable 3GI Cu: P=120W (b) Figure 21.4 (a) Three resistors connected in parallel to a battery and the equivalent single or parallel resistance. (b) Electrical power setup in a house. (credit: Dmitry G, Wikimedia Commons) II andu arges Busbar 3-phase 12M 10mm
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