Consider a circuit consisting of a battery with an emf ε and an internal resistance of r connected in series with a resistor R and a capacitor C. Show that the total energy supplied by the battery while charging the battery is equal to ε2 C .
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Consider a circuit consisting of a battery with an emf ε and an internal resistance of r connected in series with a resistor R and a capacitor C. Show that the total energy supplied by the battery while charging the battery is equal to ε2 C .
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- A voltage Δ V n resistors, each of resistance R. The circuit components are reconnected in a parallel configuration, and voltage Δ V is again applied. Show that the power consumed by the series configuration is 1/ n2 times the power consumed by the parallel configuration.A 13.0 kΩ resistor and a capacitor are connected in series and then a 20.0 V potential difference is suddenly applied across them. The potential difference across the capacitor rises to 5.0 V in 4.8 μs. Find the capacitance of the capacitor. (Your result must be in multiples of 10-10 Farads and include 2 digit after the decimal point. That means if, for example, you get a result of a 9.22x10-10 just type 9.22 in the answer box. Maximum of 5% of error is accepted in your answer. )The circuit in the figure below has been connected for a long time. Let R1 = 8.60 Ω and R2 = 4.20 Ω. (a) What is the potential difference across the capacitor?(b) If the battery is disconnected from the circuit, over what time interval does the capacitor discharge to one-tenth its initial voltage?
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