Problem 2: Acapacitor of capacitance C = 4.5 µF is initially uncharged. It is connected in C series with a switch of negligible resistance, a resistor of resistance R =16 kQ, and a battery which provides a potential difference of V3 = 180 V. in Part (a) Calculate the time constant z for the circuit in seconds. T= VB Part (b) After a very long time after the switch has been closed, what is the voltage drop Vc across the capacitor in terms of Vg? Vc= Part (c) Calculate the charge Q on the capacitor a very long time after the switch has been closed in C. Q =

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Chapter1: Units, Trigonometry. And Vectors
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Problem 2: Acapacitor of capacitance C= 4.5 µF is initially uncharged. It is connected in
series with a switch of negligible resistance, a resistor of resistance R =16 kQ, and a battery which
provides a potential difference ofV3 = 180 V.
C
in
Part (a) Calculate the time constant z for the circuit in seconds.
T=
VB
Part (b) After a very long time after the switch has been closed, what is the voltage drop Vc across the capacitor in terms of VB?
Vc=
Part (c) Calculate the charge Q on the capacitor a very long time after the switch has been closed in C.
Q =
Transcribed Image Text:Problem 2: Acapacitor of capacitance C= 4.5 µF is initially uncharged. It is connected in series with a switch of negligible resistance, a resistor of resistance R =16 kQ, and a battery which provides a potential difference ofV3 = 180 V. C in Part (a) Calculate the time constant z for the circuit in seconds. T= VB Part (b) After a very long time after the switch has been closed, what is the voltage drop Vc across the capacitor in terms of VB? Vc= Part (c) Calculate the charge Q on the capacitor a very long time after the switch has been closed in C. Q =
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