R is the reduced row echelon form of Q. Find a basis {b₁,b2, ..., bn} for the null space of Q. Q b₁ = b₂ b3 b4 b5 Fill in vectors in numerical order. Leave blank those that are not needed. = = 11 6565 7070 -704-306 4480 -1573 1694 168 74 -1073 2314 2492 -248 -108 1579 8138 8764-872-380 5553 -26132814 280 122 1783 1320, II 3317 - 794 1169 4111 ; R = 1 0 1 0 0 0 00 0 0 0 13 00 2 13 1 8 13 0 0 000 5 13 0 0 0 0 0
R is the reduced row echelon form of Q. Find a basis {b₁,b2, ..., bn} for the null space of Q. Q b₁ = b₂ b3 b4 b5 Fill in vectors in numerical order. Leave blank those that are not needed. = = 11 6565 7070 -704-306 4480 -1573 1694 168 74 -1073 2314 2492 -248 -108 1579 8138 8764-872-380 5553 -26132814 280 122 1783 1320, II 3317 - 794 1169 4111 ; R = 1 0 1 0 0 0 00 0 0 0 13 00 2 13 1 8 13 0 0 000 5 13 0 0 0 0 0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 19E
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Transcribed Image Text:R is the reduced row echelon form of Q. Find a basis {b₁,b2, ..., bn} for the null space of Q.
b₁ =
b₂
Fill in vectors in numerical order. Leave blank those that are not needed.
=
b3
b4 =
b5
=
6565 7070 -704 -306 4480
-1573 1694 168 74 - 1073
1579
2314 2492 -248 -108
8138 8764 872 -380 5553
-2613
3317
- 794
1169; R =
4111
-2814 280 122 -1783 - 1320
=
1
0
13
00 1
00 0
0
0 0
0 0 0
2
13
1
0
0
0
8
13
8
0
0
0
10 |
5
13
8
0
0
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