R h = R m2 A block of mass m1 glides frictionlessly down a circular path from a starting height h = R. At the bottom of the path it hits a block of mass 2 7 mi and which is basically at rest. After the collision, the two bricks continue to move frictionlessly up the circular path as a common body. Which expression indicates the maximum height h of the joint body above the bottom after the collision? Choose one alternative: Oh = (; -)² R mi+m2 oh = m2 R m1-m2 oh = m2 R m+m2 oh = R mi+m2 oh = R m1-m2

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Task 10
mi
R
h = R
m2
A block of mass m1 glides frictionlessly down a circular path from a starting height h = R. At the
bottom of the path it hits a block of mass 27 i and which is basically at rest. After the
collision, the two bricks continue to move frictionlessly up the circular path as a common body.
Which expression indicates the maximum height h of the joint body above the bottom after the
collision?
Choose one alternative:
m)? R
oh= (mytm2
oh =
m2
R
m1-m2
oh =
m2
R
m1+m2
oh =
mi
R
mi+m2
Oh =
R
m1-m2
Transcribed Image Text:Task 10 mi R h = R m2 A block of mass m1 glides frictionlessly down a circular path from a starting height h = R. At the bottom of the path it hits a block of mass 27 i and which is basically at rest. After the collision, the two bricks continue to move frictionlessly up the circular path as a common body. Which expression indicates the maximum height h of the joint body above the bottom after the collision? Choose one alternative: m)? R oh= (mytm2 oh = m2 R m1-m2 oh = m2 R m1+m2 oh = mi R mi+m2 Oh = R m1-m2
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