Let's try sample problem: Two balls A and B are approaching each other with velocities 5.5 m/s and 8.2 m/s respectively. The mass of ball A is 4.2 kg on the other hand ball B is 6. 6 kg. Find the velocity of the two bodies after impact, assuming that the collision is perfectly inelastic.

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tô 1 depending on the type of collision.
Let's try sample problem:
Two balls A and B are approaching each other with velocities 5.5 m/s and 8.2 m/s respectively. The mass of
ball A is 4.2 kg on the other hand ball B is 6. 6 kg. Find the velocity of the two bodies after impact, assuming
that the collision is perfectly inelastic.
Solution:
Consider "to the right" as positive and "the left" as negative direction. Ball A is moving to the right while ball B is
to the left, as shown. Therefore va1 is + and vb1 is -. The collision is perfectly
inelastic, that is, the final mass is the sum of the masses of the two balls and the final velocity
is the same for both balls therefore:
V = MAVA1+ MBVB1/ mA + mB
= (4.2 kg)(5.5 m/s) + (6.6 kg)(- 8.2 m/s)/ (4.2 kg +6.6 kg) = - 2.87
m/s
What does the negative sign indicate?
Transcribed Image Text:tô 1 depending on the type of collision. Let's try sample problem: Two balls A and B are approaching each other with velocities 5.5 m/s and 8.2 m/s respectively. The mass of ball A is 4.2 kg on the other hand ball B is 6. 6 kg. Find the velocity of the two bodies after impact, assuming that the collision is perfectly inelastic. Solution: Consider "to the right" as positive and "the left" as negative direction. Ball A is moving to the right while ball B is to the left, as shown. Therefore va1 is + and vb1 is -. The collision is perfectly inelastic, that is, the final mass is the sum of the masses of the two balls and the final velocity is the same for both balls therefore: V = MAVA1+ MBVB1/ mA + mB = (4.2 kg)(5.5 m/s) + (6.6 kg)(- 8.2 m/s)/ (4.2 kg +6.6 kg) = - 2.87 m/s What does the negative sign indicate?
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