Alex bounced a 0.59 kg rubber ball off the floor. The ball's speed just before impacting the floor was 10 m/s, and the speed just after the impact was 3.8 m/s. What impulse I, was applied to the ball by the floor? If the ball was in contact with the floor for 0.05_s, what was the magnitude of the average force applied by the floor on the ball? (Assume "up" is the positive direction.) 27. Impulse A. 15.39 kg-m/s D. 8.98 kg-m/s B. 14.95 kg-m/s E. 15.67 kg-m/s C. 14.58 kg-m/s F. 8.142 kg-m/s 1--1 28. Average Force A. 161.9 N 102.8 N B. 161.8 N 222.9 N C. 90.37 N 95.03 N 1--1 ABC DEE D. E. F.

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### Physics Problems: Impulse and Force

**Problem Statement:**
Alex bounced a 0.59 kg rubber ball off the floor. The ball's speed just before impacting the floor was 10 m/s, and the speed just after the impact was 3.8 m/s. What impulse \( I_y \) was applied to the ball by the floor? If the ball was in contact with the floor for 0.05 s, what was the magnitude of the average force applied by the floor on the ball? (Assume "up" is the positive direction.)

1. **Impulse Calculation:**

    **27. Impulse**
    - A. 15.39 kg·m/s
    - B. 14.95 kg·m/s
    - C. 14.58 kg·m/s
    - D. 8.98 kg·m/s
    - E. 15.67 kg·m/s
    - F. 8.142 kg·m/s

2. **Average Force Calculation:**
   
    **28. Average Force**
    - A. 161.9 N
    - B. 161.8 N
    - C. 90.37 N
    - D. 182.8 N
    - E. 222.9 N
    - F. 95.03 N

**Additional Problem Statement:**
A toy train engine (2.5 kg) is moving 0.25 m/s when it collides with a car (1.6 kg) moving 0.15 m/s in the same direction, and they stick together. Find the speed of the engine-car combination as they move off together.

    **29.**

For these problems, remember to use the relevant physics formulas:

- Impulse (\( I \)) is given by the change in momentum (\( \Delta p \)), where \( I = m \Delta v \).
- Average Force (\( F_{avg} \)) can be calculated using \( F_{avg} = \frac{I}{\Delta t} \), where \( I \) is the impulse and \( \Delta t \) is the time of contact.
  
For the collision problem:
- Use the principle of conservation of momentum, where \( m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \).

Make sure
Transcribed Image Text:### Physics Problems: Impulse and Force **Problem Statement:** Alex bounced a 0.59 kg rubber ball off the floor. The ball's speed just before impacting the floor was 10 m/s, and the speed just after the impact was 3.8 m/s. What impulse \( I_y \) was applied to the ball by the floor? If the ball was in contact with the floor for 0.05 s, what was the magnitude of the average force applied by the floor on the ball? (Assume "up" is the positive direction.) 1. **Impulse Calculation:** **27. Impulse** - A. 15.39 kg·m/s - B. 14.95 kg·m/s - C. 14.58 kg·m/s - D. 8.98 kg·m/s - E. 15.67 kg·m/s - F. 8.142 kg·m/s 2. **Average Force Calculation:** **28. Average Force** - A. 161.9 N - B. 161.8 N - C. 90.37 N - D. 182.8 N - E. 222.9 N - F. 95.03 N **Additional Problem Statement:** A toy train engine (2.5 kg) is moving 0.25 m/s when it collides with a car (1.6 kg) moving 0.15 m/s in the same direction, and they stick together. Find the speed of the engine-car combination as they move off together. **29.** For these problems, remember to use the relevant physics formulas: - Impulse (\( I \)) is given by the change in momentum (\( \Delta p \)), where \( I = m \Delta v \). - Average Force (\( F_{avg} \)) can be calculated using \( F_{avg} = \frac{I}{\Delta t} \), where \( I \) is the impulse and \( \Delta t \) is the time of contact. For the collision problem: - Use the principle of conservation of momentum, where \( m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \). Make sure
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