R A bullet (mass mk = 10 g) with horizontal velocity vp = 1610 m/s hits a block (mass m=2 kg) and is caught in the block. Because of that, the block starts to slide over the smooth circle-shaped surface (radius R= 1 m) of the ramp. The ramp will tip over when the horizontal component of the contact force from the block exceeds 100 N. mk At which angle 0 will this happen? Incorrect VK 74.6 Your Answer: 74.6 Correct Answer: 53.11 + 2.0%
R A bullet (mass mk = 10 g) with horizontal velocity vp = 1610 m/s hits a block (mass m=2 kg) and is caught in the block. Because of that, the block starts to slide over the smooth circle-shaped surface (radius R= 1 m) of the ramp. The ramp will tip over when the horizontal component of the contact force from the block exceeds 100 N. mk At which angle 0 will this happen? Incorrect VK 74.6 Your Answer: 74.6 Correct Answer: 53.11 + 2.0%
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A bullet (mass mk
10 g) with horizontal velocity vk
1610 m/s hits
a block (mass m = 2 kg) and is caught in the block. Because of that, the
block starts to slide over the smooth circle-shaped surface (radius
R = 1 m) of the ramp. The ramp will tip over when the horizontal
component of the contact force from the block exceeds 100 N.
At which angle 0 will this happen?
m
Incorrect
Vk
74.6
Your Answer:
74.6
Correct Answer: 53.11 + 2.0%"
Transcribed Image Text:R
A bullet (mass mk
10 g) with horizontal velocity vk
1610 m/s hits
a block (mass m = 2 kg) and is caught in the block. Because of that, the
block starts to slide over the smooth circle-shaped surface (radius
R = 1 m) of the ramp. The ramp will tip over when the horizontal
component of the contact force from the block exceeds 100 N.
At which angle 0 will this happen?
m
Incorrect
Vk
74.6
Your Answer:
74.6
Correct Answer: 53.11 + 2.0%
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