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R₂ 2.5 Ω· a 12, 13 Έ, = 18 V b I h R₁ Έz = 45 V O (I,R2) + (Igry) – Ez + (IRy) = 0 - 2 O (I,R3) – (Ig'2) + Ez + (IRy) = 0 τη 0.5 Ω 6.0 Ω 13 Μνή 0.5 Ω d 13. pa f 12 0 R3 1.5 Ω

R₂ 2.5 Ω· a 12, 13 Έ, = 18 V b I h R₁ Έz = 45 V O (I,R2) + (Igry) – Ez + (IRy) = 0 - 2 O (I,R3) – (Ig'2) + Ez + (IRy) = 0 τη 0.5 Ω 6.0 Ω 13 Μνή 0.5 Ω d 13. pa f 12 0 R3 1.5 Ω

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Apply the loop rule to loop aedcba in the figure below. E₁ = 18 V 1+ b 94 R₂ 2.5 Ω a 12 h 1₁ R₁ 13 6.0 Ω 1+ 1₁ 0.5 Ω E2 = 45 V O (1₁R₂) + (1₂₁) - E₂ + (1₂R₂) = 0 ○ (1₁R₂) - (1₂¹₂) + E₂ + (1₂R₂) = 0 O (1₁R₂) + (1₂₂) - E₁ + (1₁R₂) = 0 1 O (I₁R₁) + (₂₁) - E₁ + (1₂R₂) = 0 12 0.5 Ω 13 2 e R3 1.5 Ω
Transcribed Image Text:Apply the loop rule to loop aedcba in the figure below. E₁ = 18 V 1+ b 94 R₂ 2.5 Ω a 12 h 1₁ R₁ 13 6.0 Ω 1+ 1₁ 0.5 Ω E2 = 45 V O (1₁R₂) + (1₂₁) - E₂ + (1₂R₂) = 0 ○ (1₁R₂) - (1₂¹₂) + E₂ + (1₂R₂) = 0 O (1₁R₂) + (1₂₂) - E₁ + (1₁R₂) = 0 1 O (I₁R₁) + (₂₁) - E₁ + (1₂R₂) = 0 12 0.5 Ω 13 2 e R3 1.5 Ω
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