3. Draw a unit cell for a FCC crystal below. List all of the quantities associated with the unit cell that you can think of, with a brief (one sentence or less) description of what they are.
3. Draw a unit cell for a FCC crystal below. List all of the quantities associated with the unit cell that you can think of, with a brief (one sentence or less) description of what they are.
Related questions
Question
![3. Draw a unit cell for a FCC crystal below. List all of the quantities associated with
the unit cell that you can think of, with a brief (one sentence or less) description of
what they are.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4880849f-909d-41cc-abbf-b680a7f3a4b2%2F907c7b12-89e7-4f36-b46f-f1701c502a7d%2Ftz1nxcs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. Draw a unit cell for a FCC crystal below. List all of the quantities associated with
the unit cell that you can think of, with a brief (one sentence or less) description of
what they are.
![D = D,exp (-)
APF=
F dr
EN = E, + ER
E =
2P
HB -
Mw
PDI = MN
DID -
IC = 100(1 - e-0.25(XA-Xp)*2)
M, = E x.M,
dC
J = -D
dx
4nR
V =
3
M.
DP =
N
= exp (
N
"atoms
LD =L
Mw =
> w, M.
#atoms
PD = "atomi
A
TRSS = acosecosa
a = EE
a, = 0, + k,d?
4
V, =ar
- (소). 100
%CW =
A.
Acircle = ar?
Uz uz + V V2 + w; W2
= cos-
-Eper
y =
(už + vỷ + w¿)/už + vỷ + wž
Epar
(dF
dR
F
A.
D = D,exp(-RT)
F
A
-2y
r*
AG,
TS (MPa) = 3.45. HB
TS(psi) = 500- HB
16лу
AG =
3(AG,")
ΔΙ
-2yT,
r* =
ATm
E = In
%EL =
x100
AL
= AT
CN =
Ta
Pe(Ps-PA)
%crystallinity=PP 100
P3(Pe-P)
V = 1 +R
RA
p=T
C, - Co
= 1- erf
C, - Co
Some Young's moduli
(GPa)
Aluminum 69
Brass
100
Steel
Gold
Rubber
200
74
0.01
Some linear
coefficients of thermal
expansion (in 10
®m/m°C)
Aluminum 21-21
Brass
Steel
Gold
Rubber
18-19
10-12.5
14
80](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4880849f-909d-41cc-abbf-b680a7f3a4b2%2F907c7b12-89e7-4f36-b46f-f1701c502a7d%2Ft74db4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:D = D,exp (-)
APF=
F dr
EN = E, + ER
E =
2P
HB -
Mw
PDI = MN
DID -
IC = 100(1 - e-0.25(XA-Xp)*2)
M, = E x.M,
dC
J = -D
dx
4nR
V =
3
M.
DP =
N
= exp (
N
"atoms
LD =L
Mw =
> w, M.
#atoms
PD = "atomi
A
TRSS = acosecosa
a = EE
a, = 0, + k,d?
4
V, =ar
- (소). 100
%CW =
A.
Acircle = ar?
Uz uz + V V2 + w; W2
= cos-
-Eper
y =
(už + vỷ + w¿)/už + vỷ + wž
Epar
(dF
dR
F
A.
D = D,exp(-RT)
F
A
-2y
r*
AG,
TS (MPa) = 3.45. HB
TS(psi) = 500- HB
16лу
AG =
3(AG,")
ΔΙ
-2yT,
r* =
ATm
E = In
%EL =
x100
AL
= AT
CN =
Ta
Pe(Ps-PA)
%crystallinity=PP 100
P3(Pe-P)
V = 1 +R
RA
p=T
C, - Co
= 1- erf
C, - Co
Some Young's moduli
(GPa)
Aluminum 69
Brass
100
Steel
Gold
Rubber
200
74
0.01
Some linear
coefficients of thermal
expansion (in 10
®m/m°C)
Aluminum 21-21
Brass
Steel
Gold
Rubber
18-19
10-12.5
14
80
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)