R= 10.2 m958 m40°iW = 1050 KN- 4 mFig.4 Q.4A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay havingstrength parameters c = 58 kN/m², Ø = 0, and y = 18 kN/m³. Determine the factor ofsafety for the trial failure surface shown in Fig. 4Q.5Figure 5 shows an infinite slope with H = 32 ft and the groundwater table coinciding

The answer is found to be, Factor of safety of the given slope FOS=2.38 For explanation please see…

Answered: R= 10.2 m 95 8 m 40 HE TI tW = 1050 KN…

Engineering

Civil Engineering

R= 10.2 m 95 8 m 40 HE TI tW = 1050 KN 4 m Fig.4

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.

Question

R= 10.2 m
95
8 m
40°
iW = 1050 KN
- 4 m
Fig.4

Q.4
A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay having
strength parameters c = 58 kN/m², Ø = 0, and y = 18 kN/m³. Determine the factor of
safety for the trial failure surface shown in Fig. 4
Q.5
Figure 5 shows an infinite slope with H = 32 ft and the groundwater table coinciding

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