R= 0.15 * 40 = 62 tor Yo km -3. XL=(27FL)* Yo = 2 (3,14) Cho) (l;3263x16) C40) XL 2on for 40 km 2: R+j XL > 2:(6+520Jn /per phast to Fnd VR and IR P: S cos PR=SREOS@R Siapperent p(VA) piactive p(w). Qreactivep(vAr). 381MVA %3D : PR = 3RI 1o *0.8= 304.8 xlo Wet *0.8=304.8xlo Wast 3. PR J 3 VR TR COS OR 304.8X10 3 X220X1a xIR xo.8 IR Lo00/-36.8A VOR36.8 Lagg IR Lagging CLEAR How did he get the

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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R=0.15*40
=62 tor 4o km
-3
メレニ(2スFL)* 40
2 (3.14) Che) (l, 3263x10) CY0)
XL 2on for 4.
km
+Z= R+j XL 2:(6+j 20Jn /par phast
to find VR and IR
P=S<os O
PR=SRCOSOR
Siapperint p(VA)
piactive p(w)
reactinp(vAr)
381 MVA
PR = 381 *1o * o 8 = 304.8*lo Wat
41
PRJ3 VR TR COS ORSB04.8X1lo 3 X 220xla x IR xo8
>IRL0..1-36.8 A
OR36.8
Lagg
Lagging
IR
CLEAR
How did he get the
value inside the circle?
Transcribed Image Text:R=0.15*40 =62 tor 4o km -3 メレニ(2スFL)* 40 2 (3.14) Che) (l, 3263x10) CY0) XL 2on for 4. km +Z= R+j XL 2:(6+j 20Jn /par phast to find VR and IR P=S<os O PR=SRCOSOR Siapperint p(VA) piactive p(w) reactinp(vAr) 381 MVA PR = 381 *1o * o 8 = 304.8*lo Wat 41 PRJ3 VR TR COS ORSB04.8X1lo 3 X 220xla x IR xo8 >IRL0..1-36.8 A OR36.8 Lagg Lagging IR CLEAR How did he get the value inside the circle?
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