1. Find the Nortor eq. at (a,b) for the cct. 1402 of m 14V Ansi- 1A 612 IN= 2A, RN = 4√2 3A 512 b

Introductory Circuit Analysis (13th Edition)
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1- Find the Nortor eq. at (a,b) for the cet.
1402
of m
14V
Ansi-
1A
612
IN= 2A, RN = 4√2
3A
512
b
Transcribed Image Text:1- Find the Nortor eq. at (a,b) for the cet. 1402 of m 14V Ansi- 1A 612 IN= 2A, RN = 4√2 3A 512 b
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