r = 0r = lA rod with length e = 1.89 m and mass m = 3.31 kg has a uniform linear mass density. It ispivoted about a point a distance d from the left hand end as shown in the figure. When a constantnet torque of t = 1.53 Nm is acting on the rod it accelerates from rest to an anglular speed of@f = 6.21 rad/s in t = 6.13 s.Part 1)What is the angular acceleration of the rod over this time interval?rad/s²Part 2)What is the moment of inertia of the rod?I =kgm?Part 3)How far from the left hand end of the rod is the pivot point?d =m

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Answered: r = 0 r = l A rod with length e = 1.89…

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