A solid uniform sphere of mass 2.92 kg and diameter 78.6 cm spins about an axle through its senter. Starting with an angular velocity of 11.3 rev/s, it stops after turning through 90.7 rev with uniform acceleration. The magnitude of the net torque (in N m) acting on this sphere as it is slowing down is
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Q: F3 F1 F2
A: Given, Radius, r=0.53m F1=14.7N F2=11.1N F3=11.5N Net torque is given by, τnet=∑r×F
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A: Given data, Angels, α=48°β=35°γ=21° Length l=3.6 m
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A: The given values are, M=81.0 kgR=0.625 mr=0.230 mTu=142 Nα=1.67 rad/s2I=12MR2=1281.0 kg0.625…
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A: We will use Law of conservation of energy : 12mv2+12Iω2+12Isω22=mgh v= ωr=ω2R I of pulley = 0.0980…
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A: Mass = m = 235 g = 0.235 kg Diameter = 2r = 4.5 cm
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A solid uniform sphere of mass 2.92 kg and diameter 78.6 cm spins about an axle through its senter. Starting with an
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- Two wheels have the same mass and radius of 4.6 kg and 0.51 m, respectively. One has the shape of a solid disk. The wheels start from rest and have a constant angular acceleration with respect to a rotational axis that is perpendicular to the plane of the wheel at its center. Each turns through an angle of 13 rad in 9.5 s. Find the net external torque that acts on each wheel.A 0.71-m-diameter solid sphere can be rotated about an axis through its center by a torque of 12.8 m∗N which accelerates it uniformly from rest through a total of 170 revolutions in 15.0 s. What is the mass of the sphere? Express your answer to two significant figures and include the appropriate units.In the figure, wheel A of radiusra = 13.2 cm is coupled by belt B to wheel C of radius rc = 26.2 cm. The angular speed of wheel A is increased from rest at a constant rate of 1.17 rad/s². Find the time needed for wheel C to reach an angular speed of 142 rev/min, assuming the belt does not slip. (Hint: If the belt does not slip, the linear speeds at the two rims must be equal.) B Number i Units
- Masses m1= 8.0 kg and m2= 2.0 kg are attached at the ends of a massless rod 2.00 meters long, mounted to spin around a point 50.0 cm from one end. Calculate the rotational inertia around the mount point.A solid uniform sphere of mass 116 kg and radius 1.70 m starts from rest and rolls without slipping down an inclined plane of vertical height 5.97 m. What is the angular speed of the sphere at the bottom of the inclined plane? Give your answer in rad/s.A merry-go-round accelerates from rest to 0.74 rad/s in 33 s. Assuming the merry-go-round is a uniform disk of radius 6.0 m and mass 3.10×104 kg, calculate the net torque required to accelerate it. Express your answer to two significant figures and include the appropriate units.
- A bicycle wheel, of radius 0.300 m and mass 1.16 kg (concentrated on the rim), is rotating at 4.00 rev/s. After 54.2 s the wheel comes to a stop because of friction. What is the magnitude of the average torque due to frictional forces? ____ N⋅mA merry-go-round, having a radius of 2.5 m, is set in motion starting from rest, by students applying a force of 500 N tangential to the rim of the wheel. After five seconds of torque, the students let go and measure the rotational speed: 1.25 rad/s. What is the rotational inertia of the merry-go-round?A bar on a hinge starts from rest and rotates with an angular acceleration a = 13 + 7t, where a is in rad/s? and t is in seconds. Determine the angle in radians through which the bar turns in the first 4.53 s. 226 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four- digit accuracy to minimize roundoff error, rad
- In the figure, the block has mass m=0.45 kg and the pulley is on a frictionless horizontal axle with radius R=5.35 cm. When released from rest, the cylindrical pulley makes 10 full turns in 4.57 seconds as the block goes down. Find the rotational inertia of the pulley.In the figure, wheel A of radius ra = 13.3 cm is coupled by belt B to wheel Cof radius rc=20.4 cm. The angular speed of wheel A is increased from rest at a constant rate of 1.43 rad/s2. Find the time needed for wheel C to reach an angular speed of 58.1 rev/min, assuming the belt does not slip. (Hint: If the belt does not slip, the linear speeds at the two rims must be equal.) TA Number i UnitsTwo Thin rectangular sheets (0.28m x 0.47 m) are identical. In the first sheet the axis of rotation lies along the 0.28 inside, and in the second it lies along 0.47m side. The same torque is applied to each sheet. The first sheet starting from rest reaches its final angular velocity in 5.2 s. How long does it take for the second seat starting from rest to reach the same Angularer velocity?