Quntion of Match the peaks in this spectrum with the carbons on the structure below. A) E 273 ppm I: 1748 ppm IE: 51.9 ppm V 94 ppm B) E 51.9 ppm IE 1748 ppm I 273 ppm V 94 ppm C) E 94 ppm II I IV I 1748 ppm IE 51.9 ppm IM 273 ppm D) E 04 ppm E 174.8 ppm 273 ppm V 519 pem
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- Question 10 of 18 Match the peaks in this spectrum with the carbons on the structure below. A) I: 11.5 ppm II: 54.3 ppm II: 23.3 рpm IV: 36.2 ppm B) I: 36.2 ppm II: 11.5 ppm II: 23.3 рpm IV: 54.3 ppm C) I: 36.2 ppm II: 23.3 ppm IL III IV III: 54.3 ppm IV: 11.5 ppm D) 1: 36.2 ppm II: 54.3 ppm I: 23.3 рpm IV: 11.5 ppmQuestion 9 of 18 Match the peaks in this spectrum with the carbons on the structure below. A) : 178.1 рpm II: 68.8 ppm III: 22.5 ppm IV: 27.9 ppm B) I: 178.1 ppm II: 22.5 ppm I: 68.8 рpm IV: 27.9 ppm 160 C) I: 178.1 ppm O. II: 27.9 ppm III IV II: 22.5 ppm IV: 68.8 ppm D) I: 68.8 ppm II: 27.9 ppm II: 22.5 ppm IV: 178.1 ppmMatch the peaks in this spectrum with hydrogens on the structure below. A) H3C I H₂ 3.0 H₂ CH3 IV 2.0 ppm 1.0 1.68 ppm II: 0.99 ppm III: 2.32 ppm IV: 3.61 ppm 1: B) I: 0.99 ppm II: 1.68 ppm III: 2.32 ppm IV: 3.61 ppm C) I: II: 1.68 ppm 0.99 ppm +
- Question 12 of 18 Match the peaks in this spectrum with the carbons on the structure below. A) I: 9.5 ppm II: 28.9 ppm III: 114.5 ppm IV: 55.5 ppm B) I: 9.5 ppm Il: 55.5 ppm II: 114.5 ppm IV: 28.9 ppm C) I: 55.5 ppm II: 28.9 ppm IV III: 114.5 ppm IV: 9.5 ppm D) I: 28.9 ppm II: 9.5 ppm I: 55.5 рpm IV: 114.5 ppmQuestion 11 of 18 Match the peaks in this spectrum with the carbons on the structure below. A) I: 29.5 ppm II: 208.8 ppm III: 36.8 ppm IV: 7.7 ppm B) I: 208.8 ppm II: 29.5 ppm III: 36.8 ppm IV: 7.7 ppm C) I: 7.7 ppm II: 208.8 ppm I | I IV III: 36.8 ppm IV: 29.5 ppm D) I: 29.5 ppm II: 36.8 ppm II 208.8 рpm IV: 7.7 ppmAnalysis given IR, CNMR (written below), HNMR and mol weight: weight: 142g/mol C NMR: 4 uniques C's, small peak at 220ppm, medium peak at 50ppm, 2 strong peaks at 21 and 22ppm
- Mass spectroscopic. What is the isotopic peak pattern of each : Organic compound with 2 bromine atoms. Organic compound with 2 chlorine atoms.8 16) Chemical Formula: C.H₂O₂ IR: strong peak 1720cm-1 3H 17) Chemical Formulae: C12H18 4H, Doublet Triplet Triplet Doublet 3 5H Unknowns for 1H NMR Final Report 6 5 18) Chemical Formula: C₂H120 IR: Strong broad peak at 3200 cm-¹ 2H 5 1H 2 PPM 4 PPM 1H Quartet, 2H PPM 3 3H Singlet, 9H Triplet, 3H 2H 3H 08) Chemical Formula: C8H1204 IR: strong peak 1720cm-¹, peak at 1650cm-¹ 2H 6 5 5 9) Chemical Formula: C5H1002 IR: strong peak at 1750cm-¹ PPM 4H PPM -8x2=16+2=18-12=6/2=3 3 5x2= 10-10=0 N- 0 6H 0
- 1. 4 4000 100 50 Identify the following compounds based on the spectra given. ff11 2 20 30 T 0 220 200 180 160 140 2008 CDS-00-094 KAVEMUNERI 40 1500 50 60 120 100 ppm 70 80 500 60 40 20 07) Chemical Formula: C₂H₁N IR: weak peak at 3400cm-1 7 1H SH 2H 8) Chemical Formula: C8H1204 IR: strong peak 1720cm-1, peak at 1650cm-1 Unknowns for 1H NMR Final Report 9) Chemical Formula: C5H1002 IR: strong peak at 1750cm-1 1H (8~27 = 16-+2 = € /2=2. PPM 4H 2H 3 PPM 3H 3H 2 * H - (8x2) = 16-12=412=2 -G-H H h+1= 2 4 6H 6HWhat is the structure from the formula C10H12 and the spectra?