Quiz2:The parameters of a 1000/250V, 50HZ single phase transformer are:Ri-1.3 Ω, Χ-2.8 Ω. R-0.11Ω , X-0.2 Ω, Re-250 Ω Χ.-900 Ω. If the loadvoltage is 220V, load power is 10kW, and load power factor is 0.8 lagging.Find by using the exact equivalent circuit: (i) Input current, (ii) The inputvoltage and powver factor. (iii) The magnetizing current. (iv) The copperlosses, (v) The voltage regulation.

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Answered: Quiz2 The parameters of a 1000/250V,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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WILL SURELY GIVE AN UPVOTETOPIC: AC MACHINE INSTRUCTIONS Please write clearly and understandable wayWrite all the corresponding Given with their corresponding symbols and unitsSolve in step-by-step, no shortcut (I need to learn as a beginner)Underline twice the Final Answer PROBLEM:A single-phase transformer has a voltage ratio on open-circuit of 3300/660-V. The primary and secondary resistances are 0.82 and 0.03 respectively, the corresponding leakage reactance being 4 2 and 0.12 0. The load is equivalent to a coil of resistance 4.8Q and inductive reactance 3.60. Determine the output of the transformer in kW.a. 54b. 108c. 63d. 27
Q2/A/ What are the conditions for satisfying parallel operation of single phase transformer? Deduce an expression for the load shared by the two transformers in parallel when the transformers have equal voltage ratio? Prove your answer. B/ A 50 KVA, 2300/230 V, 60 11z transformer has a high voltage winding resistance of 0.650 and a low-voltage winding resistance of 0.0065 2. Laboratory tests showed the following results: Open circuit test: V = = 230 V, I =5.7A, P = 190 W Short circuit test: V-41.5 V, I-21.7 A, P-No wattmeter was used. 18 (2) Compute the value of primary voltage needed to give rated secondary voltage when the transformer is connected as a step-up one and is delivering 50 KVA at a power factor of 0.8 lagging. (b) Compute the efficiency under conditions of part (a).
A conventional phase transformer given in the figure will be connected as an autotransformer in two different ways. Each For a connection, find the input and output powers by drawing the connection. a) Connection of 1220 / 220V autotransformer b) 1000 / 1220V autotransformer connection
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The primary of a certain transformer takes 0.7 A at a power factor of 0.5 when it isconnected across 200 V, 50 Hz supply and the secondary is on open circuit. The number ofturns on the primary is twice that on the secondary. A load taking 10 A at a lagging powerfactor of 0.8 is now connected across the secondary. Calculate the primary current andpower factor. Draw the phasor diagram.
925 3- The approximate equivalent circut of is to be determined. The open-circuit at 0 20KVA, 8000/240 V 60 Hz transformar short-circut tests that were performed transformer. primary side gave the following results. Open - Circut Test V₁x = 8000 Iloc=0-214 A Ploc = 400 W Short-Circuit Test |Visc = 489V 5₁s = 2.5A Pisc = 240k/ al Find the components of the magnetising branch i referred to the primary side b) Find the Components of the equivalent series impedence referred to the primary side. 119 210 2 15 16
Q/A single-phase transformer with a capacity of 100 kVA and a voltage of 2000/400 and the equivalent circuit elements are: As follows R1 = 0.1 02 x1 = 0.2 2 R2 = 0.25 2 X2 = 0.75 2 RO = 500 XO = 150 Q and feeds a load of 90 kVA at a voltage of 2000 volts and a power factor of 8.0 in delay. Calculate voltage and current Primary Royl ww JX eql
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The folkwing results were obtained on 220/440V transformer First Test:120W,12A, 30 V Second Test: 70 w, 3A, 225V Cakulate the circuit constants and show them on an approximate equivakent circut.
A 9KVA, 360V/180V transformer has been tested to determine its equivalent circuit. The open circuit test data when high voltage side is open: loc=1.8A, Poc=200W. The short circuit test data when low voltage side is short circuited: Vsc=40V, Psc-230W. Use approximate equivalent circuit. Calculate equivalent resistance primary value. 0.736 0.023 0.368 0.092 0.184

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