Quiz 2: 5. A horizontal curve is laid out with the point of curve, PC, station and the length of long chord, LC, as shown. The curve radius, R, is 620 ft. With stationing around the curve, the stationing of the point of tangent, PT, is most near to (A) sta 6+20 (B) sta 10+42 PT (C) sta 14+02 LC = 980 ft (D) sta 14+64 sta 4+22 PC I 96°18' R 620 ft

Quiz 2: 5. A horizontal curve is laid out with the point of curve, PC, station and the length of long chord, LC, as shown. The curve radius, R, is 620 ft. With stationing around the curve, the stationing of the point of tangent, PT, is most near to (A) sta 6+20 (B) sta 10+42 PT (C) sta 14+02 LC = 980 ft (D) sta 14+64 sta 4+22 PC I 96°18' R 620 ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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3 Horizontal curves You are asked to design a 5-degree horizontal curve with an intersection angle at the center equals 60°15'. The station of point of curvature is 155 + 26.5 ft. Calculate the following: A. Length of the curve B. Station of the point of tangency (PT) C. For first two whole stations next to PC, calculate the degree of deflection from the PC and chord length from the previous point along the horizontal curve.
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