questions. Assume A() = A(3) = 20 in², A (2) = 40 in²,1) = I(3) = 200 in. I) = 400 in'. and E 29,000 ksi. 6 kip 71 2.4 kip/ft 2 3 Tx, 1.2 kip/ft 15 ft 30 ft (c) Determine the following: (i) The shear for member (3) at x₁ = 6 ft = kip (ii) The moment for member (2) at x2 = =6ft = kipft (iii) The maximum negative moment for member (2) kip ft (iv) The location of zero shear for member (3) at x₁ = ft (v) The rotation at joint 2= rad (Show the direction arrow.) (vi) The maximum vertical displacement of the frame = in (vii) The maximum horizontal displacement of the frame = in
questions. Assume A() = A(3) = 20 in², A (2) = 40 in²,1) = I(3) = 200 in. I) = 400 in'. and E 29,000 ksi. 6 kip 71 2.4 kip/ft 2 3 Tx, 1.2 kip/ft 15 ft 30 ft (c) Determine the following: (i) The shear for member (3) at x₁ = 6 ft = kip (ii) The moment for member (2) at x2 = =6ft = kipft (iii) The maximum negative moment for member (2) kip ft (iv) The location of zero shear for member (3) at x₁ = ft (v) The rotation at joint 2= rad (Show the direction arrow.) (vi) The maximum vertical displacement of the frame = in (vii) The maximum horizontal displacement of the frame = in
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Assume A = A = 20 in², A = 40 in², I = I= 200 in. Ig = 400 in and E= 29,000 ksi.
Determine e following: (i) The shear for member (3) at x,= 6 ft = kip (ii) The moment for member (2) at x, = 6 ft = kipfu (iii) The maximum negative moment for member (2) = kip ft (iv) The location of zero shear for member (3) at x,= ft (v) The rotation at joint 2= rad (Show the direction arrow.) (vi) The maximum vertical displacement of the frame in (vii) The maximum horizontal displacement of the frame in
Transcribed Image Text:questions. Assume A() = A(3) = 20 in², A (2) = 40 in²,1) = I(3) = 200 in. I) = 400 in'.
and E 29,000 ksi.
6 kip
71
2.4 kip/ft
2
3
Tx,
1.2 kip/ft
15 ft
30 ft
(c) Determine the following:
(i) The shear for member (3) at x₁ = 6 ft =
kip
(ii) The moment for member (2) at x2 =
=6ft =
kipft
(iii) The maximum negative moment for member (2)
kip ft
(iv) The location of zero shear for member (3) at x₁ =
ft
(v) The rotation at joint 2=
rad
(Show the direction arrow.)
(vi) The maximum vertical displacement of the frame =
in
(vii) The maximum horizontal displacement of the frame =
in
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