Questions 6-10 are related to the following As a statistics course assignment you are to build a 95% confidence interval for the mean monthly rental for two- bedroom apartments in Marion County. A random sample of apartments yields the following data. 1065 1070 1380 910 1130 1175 1130 1100 1225 1110 1140 1110 985 1020 1165 1065 1255 1030 1195 1005 975 1150 1085 1180 860 1060 1265 1095 1375 1100 1225 1360 1365 1145 1415 1165 1115 1075 1065 1115 1040 1265 1155 1225 1165 1125 1175 1090 990 1245 1115 1250 875 980 1185 1295 1085 1495 1265 1210 1080 1205 1030 1235 1055 1220 1175 1155 1035 1280 1300 1160 1270 1195 1115 1125 980 945 1275 900 1075 - 940 1285 960 1145 865 1020 1020 1215 1105 820 955 1090 1120 965 1085 870 1145 970 1195 985 1140 1145 1170 1140 1170 1095 1025 1120 1115

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**Educational Content for Statistical Analysis:**

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**Variance and Confidence Intervals in Sample Data**

1. **The estimated variance of the sample mean is:**

   a. 143.21  
   b. 155.66  
   c. 15752.64  
   d. 14492.42  

2. **The margin of error for the 95% confidence interval is:**

   a. $28.70  
   b. $26.09  
   c. $23.72  
   d. $21.56  

3. **The 95% interval estimate for the mean rent is:**

   a. $1,069 - $1,174  
   b. $1,081 - $1,162  
   c. $1,091 - $1,152  
   d. $1,098 - $1,145  

4. **If you were asked to narrow the 95% margin of error to $10, how many apartments would you need to include in your sample? For planning, use the sample standard deviation above.**

   a. 702  
   b. 706  
   c. 654  
   d. 606  

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**Note on Confidence Intervals and Margin of Error:**

- Confidence intervals are used to estimate the range within which a population parameter lies, based on sample data.
- The margin of error indicates the range’s precision and is used to express the variability in estimates.

**Questions 13 & 14**

The following scenario is related to finding statistical estimates:

- A random sample of full coverage auto insurance policy costs is given.
- This data is used to build a 95% interval estimate for the mean cost of a full coverage policy.

---

This content provides insights into statistical estimation techniques, emphasizing the estimation of population parameters based on sample data, variance, and confidence intervals.
Transcribed Image Text:**Educational Content for Statistical Analysis:** --- **Variance and Confidence Intervals in Sample Data** 1. **The estimated variance of the sample mean is:** a. 143.21 b. 155.66 c. 15752.64 d. 14492.42 2. **The margin of error for the 95% confidence interval is:** a. $28.70 b. $26.09 c. $23.72 d. $21.56 3. **The 95% interval estimate for the mean rent is:** a. $1,069 - $1,174 b. $1,081 - $1,162 c. $1,091 - $1,152 d. $1,098 - $1,145 4. **If you were asked to narrow the 95% margin of error to $10, how many apartments would you need to include in your sample? For planning, use the sample standard deviation above.** a. 702 b. 706 c. 654 d. 606 --- **Note on Confidence Intervals and Margin of Error:** - Confidence intervals are used to estimate the range within which a population parameter lies, based on sample data. - The margin of error indicates the range’s precision and is used to express the variability in estimates. **Questions 13 & 14** The following scenario is related to finding statistical estimates: - A random sample of full coverage auto insurance policy costs is given. - This data is used to build a 95% interval estimate for the mean cost of a full coverage policy. --- This content provides insights into statistical estimation techniques, emphasizing the estimation of population parameters based on sample data, variance, and confidence intervals.
**Educational Website Transcription:**

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**Questions 6-10 are related to the following**

As a statistics course assignment, you are to build a 95% confidence interval for the mean monthly rental for two-bedroom apartments in Marion County. A random sample of apartments yields the following data:

| 1065 | 1110 | 1085 | 1145 | 1165 | 1295 | 1175 | 945  | 1215 | 1195 |
|------|------|------|------|------|------|------|------|------|------|
| 1070 | 990  | 1180 | 1145 | 1175 | 1085 | 1155 | 1275 | 1105 | 985  |
| 1380 | 1150 | 860  | 1115 | 1125 | 1495 | 1035 | 900  | 820  | 1140 |
| 1165 | 1300 | 1265 | 1175 | 1300 | 1120 | 1280 | 1075 | 955  | 1145 |
| 1170 | 1030 | 1170 | 1265 | 1210 | 1300 | 940  | 1090 | 1170 | 1195 |
| 1305 | 1235 | 1125 | 1235 | 1265 | 1020 | 1145 | 1285 | 1185 | 1065 |
| 1035 | 1375 | 1105 | 1115 | 1050 | 1270 | 960  | 965  | 1170 |      |
| 1120 | 875  | 1325 | 960  | 1300 | 1195 | 1145 | 1085 | 1170 |      |
| 1110 | 1055 | 1185 | 1120 | 1035 | 1175 | 1275 | 860  | 870  | 1025 |
| 1150 | 1125 | 975  | 985  | 1085 | 1105 | 1125 | 1020 | 1145 | 1145 |
| 1370 | 970  | 1225 |
Transcribed Image Text:**Educational Website Transcription:** --- **Questions 6-10 are related to the following** As a statistics course assignment, you are to build a 95% confidence interval for the mean monthly rental for two-bedroom apartments in Marion County. A random sample of apartments yields the following data: | 1065 | 1110 | 1085 | 1145 | 1165 | 1295 | 1175 | 945 | 1215 | 1195 | |------|------|------|------|------|------|------|------|------|------| | 1070 | 990 | 1180 | 1145 | 1175 | 1085 | 1155 | 1275 | 1105 | 985 | | 1380 | 1150 | 860 | 1115 | 1125 | 1495 | 1035 | 900 | 820 | 1140 | | 1165 | 1300 | 1265 | 1175 | 1300 | 1120 | 1280 | 1075 | 955 | 1145 | | 1170 | 1030 | 1170 | 1265 | 1210 | 1300 | 940 | 1090 | 1170 | 1195 | | 1305 | 1235 | 1125 | 1235 | 1265 | 1020 | 1145 | 1285 | 1185 | 1065 | | 1035 | 1375 | 1105 | 1115 | 1050 | 1270 | 960 | 965 | 1170 | | | 1120 | 875 | 1325 | 960 | 1300 | 1195 | 1145 | 1085 | 1170 | | | 1110 | 1055 | 1185 | 1120 | 1035 | 1175 | 1275 | 860 | 870 | 1025 | | 1150 | 1125 | 975 | 985 | 1085 | 1105 | 1125 | 1020 | 1145 | 1145 | | 1370 | 970 | 1225 |
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