Question(14): A researcher wanted to know whether children  who live in two different neighbourhood (Willowdale and Forresthill) got different amount of excerise. Children were randomly selected from the two neighbourhoods (40 in each). and filled out the daily activity report to measure their excerise. The number of minutes of excerise  were tallied and recorded. The  The researcher then  conducted an independent  sample t test  using MS-EXCELL. The result are shown in the image below. Inspect the MS- EXCELL output.Did the researcher conduct their t test assuming equal variance.? Write out Step 5 by including both the formal answer and the conclusion. The five steps are: Step 1:State the hypotheses  and identify the claim. Step 2: Compute the test value Step 3: Compute the critical value. Step 4:Make the decision (reject or not reject) Step 5:Summaize the results. Note: you only need to submit step 5, and round snswer to decimal places MS-EXCELL output:                                                                                  Willowdale                       Forresthill mean                                                                           108.65                                   86.93 variance                                                                       2601.67                             1238.99 observations                                                                   40                                       40 pooled variance                                                           1920.13 hypothisized mean difference                                                                          0 df                                                                                     78 t stat                                                                                 2.22 P(T<=t)(one tail)                                                              .01 t critical value(one tail)                                                       1.66 P(T<=t)(two tail  )                                                                .03 t critical value (two tail)                                                       1.99

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Question(14):

A researcher wanted to know whether children  who live in two different neighbourhood (Willowdale

and Forresthill) got different amount of excerise. Children were randomly selected from the two

neighbourhoods (40 in each). and filled out the daily activity report to measure their excerise. The number of minutes of excerise  were tallied and recorded. The  The researcher then  conducted an independent  sample t test  using MS-EXCELL. The result are shown in the image below. Inspect the

MS- EXCELL output.Did the researcher conduct their t test assuming equal variance.? Write out Step 5

by including both the formal answer and the conclusion.

The five steps are:

Step 1:State the hypotheses  and identify the claim.

Step 2: Compute the test value

Step 3: Compute the critical value.

Step 4:Make the decision (reject or not reject)

Step 5:Summaize the results.

Note: you only need to submit step 5, and round snswer to decimal places

MS-EXCELL output:

                                                                                 Willowdale                       Forresthill

mean                                                                           108.65                                   86.93

variance                                                                       2601.67                             1238.99

observations                                                                   40                                       40

pooled variance                                                           1920.13

hypothisized mean

difference                                                                          0

df                                                                                     78

t stat                                                                                 2.22

P(T<=t)(one tail)                                                              .01

t critical value(one tail)                                                       1.66

P(T<=t)(two tail  )                                                                .03

t critical value (two tail)                                                       1.99

 

                                                                         

 

 

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