Question.03In a Hartnell governor, Figure Q3, the length of the ball is 190 mm, that of the sleevearm is 140 mm, and the mass of each ball is 3.2 kg. The distance of the pivot of eachbell-crank lever from the axis of rotation is 170 mm, and the speed when the ball isvertical is 320 rev/min. The speed is to increase 0.6 percent for a lift of 12 mm of thesleeve.(a) Neglecting the dead load on the sleeve, find the necessary stiffness of thespring and the required initial compression.(b) What spring stiffness and initial compression would be required if the speed isto remain the same for the changed position of the sleeve (ie. the governor isto be isochronous).F190mm140mm+170mm-Figure Q3LARAAAAAAAg Example C04.03r= 0-17 m:. P,= 0-0804 × 300² × 0-17= 1230 NAt 300 rev/min,QuestionIn a Hartnell governor, the length of the ball is 190 mm, that of the sleeve arm is 140mm, and the mass of each ball is 2.7 kg. The distance of the pivot of each bell-cranklever from the axis of rotation is 170 mm, and the speed when the ball is vertical is 300rev/min. The speed is to increase 0.6 percent for a lift of 12 mm of the sleeve.For a 0-6 per cent increase in speed, N= 301-8 rev/min0-19r = 0-17 + 0-012 ×0-14and= 0-1863 m(a) Neglecting the dead load on the sleeve, find the necessary stiffness of the springand the required initial compression.(b) What spring stiffness and initial compression would be required if the speed isto remain the same for the changed position of the sleeve (i.e. the governor is to:. at 301-8 řev/min,P2= 0-0804 x 301-8² × 0-1863= 1364 NР, — Р,compression of springi spring stiffness =be isochronous).1364 – 12300-012= 11 160 N/mSolutionInitial compressioninitial spring forcestiffness12300-11 m11 160190mm(b)For isochronism, the equilibrium speed remains constant for all radiiof rotation. If P, and P, are the spring forces for isochronism correspond-ing to radii of rotation of 0-17 m and 0-1863 m respectively,140mm170mmthenP= 0-0804 x 300 × 0-17 = 1231 NFigure Q4.3andP= 0-0804 x 3002 x 0-1863 = 1349 N1349 – 1231(a): stiffness == 9830 N/m0-012Let P be the force exerted by the spring and F the centrifugal force on one ball.Then, taking moments about O, Figure Q4.3,1231Initial compression =9830= 0-1252 mFx0.19 — P/2 х 0.14Note:(27.2-7Px 0-14Isochronism means the condition of occurring at the same time as anotheri.e.X+ x 0-19 =event.:: P= 0-0804N²r

Answered: Image /qna-images/answer/275efd97-b08d-4bb6-9412-fd5f8bb52f59.jpg

Question.03 In a Hartnell governor, Figure Q3, the length of the ball is 190 mm, that of the sleeve arm is 140 mm, and the mass of each ball is 3.2 kg. The distance of the pivot of each bell-crank lever from the axis of rotation is 170 mm, and the speed when the ball is vertical is 320 rev/min. The speed is to increase 0.6 percent for a lift of 12 mm of the sleeve. (a) Neglecting the dead load on the sleeve, find the necessary stiffness of the spring and the required initial compression. (b) What spring stiffness and initial compression would be required if the speed is to remain the same for the changed position of the sleeve (i.e. the governor is to be isochronous). 190mm 140mm- +170mm-

Question.03 In a Hartnell governor, Figure Q3, the length of the ball is 190 mm, that of the sleeve arm is 140 mm, and the mass of each ball is 3.2 kg. The distance of the pivot of each bell-crank lever from the axis of rotation is 170 mm, and the speed when the ball is vertical is 320 rev/min. The speed is to increase 0.6 percent for a lift of 12 mm of the sleeve. (a) Neglecting the dead load on the sleeve, find the necessary stiffness of the spring and the required initial compression. (b) What spring stiffness and initial compression would be required if the speed is to remain the same for the changed position of the sleeve (i.e. the governor is to be isochronous). 190mm 140mm- +170mm-

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: Figure Q2 illustrates a two-finger mechanical gripper. Assume that a mass of 10kg is to be grasped…

A: Given: The weight, W = 10 kg The coefficient of friction, f = 0.2 The safety factor, n = 2

Q: Determine the reaction forces at the four contact points A, B, C and D. Small: Mass of 1.02 kg…

Q: R Known values: G h TTT P R m 2600 lb 1.4 ft 1.3 slug 0.004s 8 gravity

Q: A lean disk of mass M and sweep A is associated by two springs of spring steady k to two settled…

A: given; →mass of disk =M→radius of disk =R→stiffness of spring=k→frequency=?

Q: In lifting a 30 Kg container with a class 1 lever, it is noted that for every 2 m distance input the…

Q: Your team is prototyping a simple braking system for your model car. The 3.4 kg wheel with a radius…

Q: ramophone is driven by a rernor. The mass of each centre of a leaf spring is

A: given:b=5mmt=0.125mmE=210KN/mm2m=20g

Q: Q1/ In a Hartnell governor, the length of the ball arms is 190 mm, that of the sleeve arms is 140…

A: Introduction: The Hartnell Governor is essentially a centrifugal governor with a spring-loaded…

Q: 4. Consider a mass of 500 g placed at the end of a spring with stiffness constant 100 N/m and…

Q: A luggage handler pulls a 20.0 kg suitcase up a amp inclined at 32.0° above the horizontal by a…

Q: Part (A)- In a Hartnell governor, the mass of each ball is 6 kg. The lengths of ball arm and sleeve…

Q: FACULTY OF SCIENCES QUESTION NO. 2: In Figure 2, a block m; (m; =1.0 kg) on a frictionless inclined…

Q: Plz solve correctly

A: Part (a): Finding the Speed of the 10-kg BlockInitially, the system is at rest, so the total…

Q: Five masses m1, m2, m3 m4 and m5 are 150 kg, 250 kg, 190 kg , 120 kg and 210 kg respectively. The…

A: Value of masses:- m1=150kg, m2=250kg, m3=190kg, m4=120kg, m5=210kg Radius of rotation:- r1=0.2m,…

Q: A winch, located at M, pulls a box up an incline with a cable. The distance from the box to the…

A: Given:To find:Speed of the box when it reaches the winch M.

Q: A flypress has two rotating spheres, each of mass 5 kg, fixed to a horizontal arm, s that they are…

Q: Q9A Hartnell type governor with a central spring under compression has balls each of mass 2 kg. The…

A: To find:The value of equilibrium speed corresponding to a sleeve of Given:The value of mass, The…

Q: h Wil S k www

A: Given situation is, Using the conservation of energy,

Q: # B A 20cm Figure 1. Sketch of the problem. The 20 kg disc A is attached to the 10 kg block B using…

Q: Don't Use Chat GPT Will Upvote And Give Handwritten Solution Please

A: Solution:

Q: Form the figure shown, a flexible belt placed around a rotating drum of 4-inch radius acts as a…

A: Given Givenr=4inμ=0.7T=400 lb-in

Q: b m

Q: A spur pinion of pitch diameter 50 mm rotates at 200 rad/s and transmits 3 kW power. The pressure…

A: Given Data D=50 mm w=200 rad/s P=3 kW Pressure angle=20°

Q: The diagram below shows a wheel(disk) of radius R and mass M = 2m which is attached via a string to…

Q: 1.p.m. Añs. Example 18.7. A loaded Porter governor has four links each 250 mm long, two revolving…

A: A loaded porter governor Where M is the mass of the sleeve m is the mass of each ball h is the…

Q: You are designing a system for moving aluminum cylinders from the ground to a loading dock. You use…

A: given data length (L) = 2m θ = 37° mass ( m) of cylinder = 450 kg radius R of cylinder = 0.300 m

Q: A cylindrical roller 300mm diameter and a mass of 50kg. rest on a horizontal floor with its curved…

A: Given data: Mass of the roller, m = 50 kg diameter of the roller, D = 300 mm radius of the roller,…

Q: adius of 10.5 cm. Due to the mal adjustment of spring, the equilibrium speed of governor at top…

Q: e top arms make 45° with the axis of rotation in the equilibrium position, find the range of speed…

A: M=mass of contol load=18 kgm=mass of ball =2kgF= friction =14Nh= height of governorcos 45 =h250from…

Q: 2.1 2.2 QUESTION 1 A trolley of mass 200 kg has to be pulled up an incline of 60° with an…

A: Question 1: Given: The mass of trolley, M = 200 kg The mass of pully, m = 60 kg The acceleration of…

Q: oblem 8.45 To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire…

A: The mass of satellite is The mass of each rocket is The radius is The final speed is The time taken…

Concept explainers

Clutches, Brakes, Couplings, and Flywheels

The clutch is described as a machine element used to connect or disconnect two shafts together to transmit torque or power. The clutch works on the principles of friction. The clutch is commonly used in automobiles to transfer power from the driving shaft to the driven shaft.

Question

100%

Example C04.03
r= 0-17 m
:. P,= 0-0804 × 300² × 0-17
= 1230 N
At 300 rev/min,
Question
In a Hartnell governor, the length of the ball is 190 mm, that of the sleeve arm is 140
mm, and the mass of each ball is 2.7 kg. The distance of the pivot of each bell-crank
lever from the axis of rotation is 170 mm, and the speed when the ball is vertical is 300
rev/min. The speed is to increase 0.6 percent for a lift of 12 mm of the sleeve.
For a 0-6 per cent increase in speed, N= 301-8 rev/min
0-19
r = 0-17 + 0-012 ×
0-14
and
= 0-1863 m
(a) Neglecting the dead load on the sleeve, find the necessary stiffness of the spring
and the required initial compression.
(b) What spring stiffness and initial compression would be required if the speed is
to remain the same for the changed position of the sleeve (i.e. the governor is to
:. at 301-8 řev/min,
P2= 0-0804 x 301-8² × 0-1863
= 1364 N
Р, — Р,
compression of spring
i spring stiffness =
be isochronous).
1364 – 1230
0-012
= 11 160 N/m
Solution
Initial compression
initial spring force
stiffness
1230
0-11 m
11 160
190mm
(b)
For isochronism, the equilibrium speed remains constant for all radii
of rotation. If P, and P, are the spring forces for isochronism correspond-
ing to radii of rotation of 0-17 m and 0-1863 m respectively,
140mm
170mm
then
P= 0-0804 x 300 × 0-17 = 1231 N
Figure Q4.3
and
P= 0-0804 x 3002 x 0-1863 = 1349 N
1349 – 1231
(a)
: stiffness =
= 9830 N/m
0-012
Let P be the force exerted by the spring and F the centrifugal force on one ball.
Then, taking moments about O, Figure Q4.3,
1231
Initial compression =
9830
= 0-1252 m
Fx0.19 — P/2 х 0.14
Note:
(27.
2-7
P
x 0-14
Isochronism means the condition of occurring at the same time as another
i.e.
X+ x 0-19 =
event.
:: P= 0-0804N²r

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Clutches, Brakes, Couplings and Flywheels

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Dynamics of Rigid Bodies
QUESTION 14 The collar of mass m = 77 kg in Figure Q14 slides outwards with an initial radial velocity vo = 0.58 m-s-1 from zero initial radial position (see dashed box) along a smooth rotating shaft (see unit vector ur). The shaft rotates with constant angular speed of w = 2 rad-s-1. Determine the magnitude of the constant force F (N) that needs to be applied in the radial direction (pointing towards the centre of the shaft) in order to decelerate the collar to zero radial velocity the moment when the collar reaches a radial position r = 0.19 m. Consider motion in a horizontal plane, such that gravity can be ignored. Provide only the numerical value (in Newtons) to zero decimal places and do not include the units in the answer box. Ur F m Vo Figure Q14: Rotating collar-shaft system
Ruler of the "Porter" model, with the upper and lower arms of 178 mm each, fixed by a hinge 38 mm away from the center of rotation. The rotating balls have a mass of 1.15 kg each, and the axial weight affecting the bushing is 20 kg. The ruling commotion began =154. Elevation at 280rpm - The joints are at an angle of 30 to the vertical. Assuming that the force of friction is constant, find the minimum and maximum rotational speed when mg The angle of inclination of the arms to the vertical is 45
Theory of machines
Q2: A curved path has banked angle 12° and 30 m radius of rotation was designed for four-wheeled Trolley of total mass 2500 kg to move on track ofr 1 m gauge at 35 km/hr. For this vehicle all wheels have an external diameter of 0.5 m and each pair of axle weight is 1800 N and radius of gyration of 0.2 m. The center of gravity is located 1 m above the groun level. Within this mechanism, determine the limited pressure on each rail.
Instead of using the system shown in Figure 3.2.6a to raise the mass m2, an engineer proposes to use two simple machines, the pulley and the inclined plane, to reduce the weight required to lift m2. The proposed design is shown in Figure P3.12. The pulley inertias are negligible. The available horizontal space limits the angle of the inclined plane to no less than 30°. a. Suppose that the friction between the plane and the mass m2 is negligible. Determine the smallest value m1 can have to lift m2. Your answer should be a function of m2 and 0. m₂ m28 (b) T₁ m₁ mig
A relatively thin disc with uniformly distributed mass is mounted on a shaft which rotates at 1000 RPM. To conduct a test, two extra masses are added to the disc at the positions shown in Figure Q10. Masses A and B introduce known unbalances of 2 kgmm and 4 kgmm, respectively. Determine the angular location of the correction mass measured from y-axis in the clockwise direction and the centrifugal force that it needs to produce in order to balance the system. YA A 30° B 70° X TIT TIT N
4.14. The system illustrated in Figure 4.26 is comprised of a board of length / with uniform mass per unit length of p. It sits on top of two counter-rotating cylinders, which are rotating with an angular velocity of @ in the directions indicated and are separated by a distance 1/2. You may assume that is large enough that the points of contact between the board and cylinders are always slipping and that the coefficient of dynamic friction between the board and cylinders is μ. If the board is not centered on the two cylinders, then the normal force will be greater on the side to which it is displaced because more of the weight of the board will be supported on that side. For example, in the figure, the normal force between the board and cylinder will be greater at the left cylinder, and this will cause a net force to the right. Let x denote the distance that the center of the board is displaced from the center of the two cylinders, as is illustrated in the figure, and determine the…
Needs Complete typed solution with 100 % accuracy.
In a spring-loaded governor of the Hartnell type, the lengths of the horizontal and the vertical arms of the bell- crank lever are 40 mm and 80 mm respectively. The mass of each ball is 1.2 kg. The extreme radii of rotation of the balls are 70 mm and 105 mm. The distance of the fulcrum of each bell- crank lever is 75 mm from the axis of rotation of the governor. The minimum equilibrium speed is 420 rpm and the maximum equilibrium speed is 4% higher than this. Neglecting the obliquity of the arms, determine the (i) spring stiffness, (ii) initial compression, and (iii) equilibrium speed corresponding to radius of rotation of 95 mm.