Question Which of the following statements about binary search and binary search trees (BSTS) are true? Unless otherwise specified, assume that the binary search and binary search tree implementations are the ones from lecture. Answer Mark all that apply. OIn the worst case, the number of key compares to compute *the number of keys strictly less than an arbitrary key* in a sorted array is - log_2n O For any BST containing n = 2^h - 1 distinct keys, it is possible to construct a perfectly balanced BST on the same n keys in linear time. O For any BST node x, the successor of x (the node containing the next largest key) is the leftmost node in the right subtree of x. OIn the best case, the number of key compares to find a median in a sorted array of n distinct keys is - log_2 n. OIn the worst case, the number of key compares to compute *the smallest key strictly greater than an arbitrary key in a sorted array is - log_2 n.

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Which of the following statements about binary search and binary search trees (BSTS) are true? Unless otherwise specified, assume that the binary search and binary search tree implementations
are the ones from lecture.
Answer
Mark all that apply.
UIn the worst case, the number of key compares to compute *the number of keys strictly less than an arbitrary key* in a sorted array is ~ log_2 n.
For any BST containing n = 2^h - 1 distinct keys, it is possible to construct a perfectly balanced BST on the same n keys in linear time.
For any BST node x, the successor of x (the node containing the next largest key) is the leftmost node in the right subtree of x.
In the best case, the number of key compares to find a median in a sorted array of n distinct keys is ~ log_2 n.
UIn the worst case, the number of key compares to compute *the smallest key strictly greater than an arbitrary key* in a sorted array is - log_2 n.
Transcribed Image Text:Question Which of the following statements about binary search and binary search trees (BSTS) are true? Unless otherwise specified, assume that the binary search and binary search tree implementations are the ones from lecture. Answer Mark all that apply. UIn the worst case, the number of key compares to compute *the number of keys strictly less than an arbitrary key* in a sorted array is ~ log_2 n. For any BST containing n = 2^h - 1 distinct keys, it is possible to construct a perfectly balanced BST on the same n keys in linear time. For any BST node x, the successor of x (the node containing the next largest key) is the leftmost node in the right subtree of x. In the best case, the number of key compares to find a median in a sorted array of n distinct keys is ~ log_2 n. UIn the worst case, the number of key compares to compute *the smallest key strictly greater than an arbitrary key* in a sorted array is - log_2 n.
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