Question: Velocity profile of a flow in an open channel is defined by the equation given below, where depth of fluid in channel (h) is 10 cm, and maximum flow velocity (Umax) reached at the top is 50 cm/s. u = Sin (Umax * T * y) Calculate velocity of flow (u, m.s¹¹) and shear stress (t, Pa) for y = 0 mm, 5 mm, 20, 50 and 100 mm height from bottom for dynamic viscosity μ = 0,00113 Pa.s. Draw curves for velocity and shear stress distribution with respect to depth.
Question: Velocity profile of a flow in an open channel is defined by the equation given below, where depth of fluid in channel (h) is 10 cm, and maximum flow velocity (Umax) reached at the top is 50 cm/s. u = Sin (Umax * T * y) Calculate velocity of flow (u, m.s¹¹) and shear stress (t, Pa) for y = 0 mm, 5 mm, 20, 50 and 100 mm height from bottom for dynamic viscosity μ = 0,00113 Pa.s. Draw curves for velocity and shear stress distribution with respect to depth.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Question: Velocity profile of a flow in an open channel is defined by the equation given below, where
depth of fluid in channel (h) is 10 cm, and maximum flow velocity (Umax) reached at the top is 50 cm/s.
u = Sin (Umax * π * y)
Calculate velocity of flow (u, m.s¹) and shear stress (T, Pa) for y = 0 mm, 5 mm, 20, 50 and 100 mm
height from bottom for dynamic viscosity μ = 0,00113 Pa.s. Draw curves for velocity and shear stress
distribution with respect to depth.
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