Question OneThe cost of two generators (in $) as a function of power (in MW) is given:C1 = 0.1P? + 35P, + 3200150 < PI <300C2 = 0.225P? + 20P2 + 200050 < P2 <200Neglecting the system's losses, answer the following:1) What is the condition on the two generators that must be met to achieve an optimal power dispatch?2) What will be the incremental cost of Generator 1 when it is required to generate 200 MW?3) If the demand is 400 MW, determine the incremental cost of the generators that will yield the least possible costwhile meeting the demand requirement

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Answered: Question One The cost of two generators…

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Question One The cost of two generators (in $) as a function of power (in MW) is given: C1 = 0.1P? + 35P, + 3200 150

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.

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