Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness I. Which metal is more ductile? Why? 900 -Metal A E 600 Metal B 300 0.00 a02 004 a.06 0.08 0.10 0.12 014 Strain, matm FIGURE P1.16 Strees, MPa

Q: 400 200 Strain 0.05 0.10 0.15 0.20 From your graph, plotting the yield stress against 1/vd, you…

A:

Q: Fc FA Fa Fc

A: According to given data Fa , Fb , Fc principal stresses are shown in three elements  We need to…

Q: 1.17 Figure P1.17 shows the stress-strain relations of metals A and B during tension tests until…

A: Any pressure of a solid object creates a stretched internal stress, similar to the spring-turning…

Q: A tension test for a steel alloy results in the stress-strain diagram shown in Figure. Calculate the…

A: Consider the graph,

Q: 2. A steel with E = 29 000 ksi with a rectangular cross-section is bent over a rigid mandrel with R…

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Q: Determine the following: a. Young's modulus within the linear portion b. Tangent modulus at a stress…

A: a).Young's Modulus : At the proportional limit, stress is directly proportional to strain stress α…

Q: A tensile test was done on a steel specimen with the gauge length of 525 and a stress of 175 MPa. If…

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Q: Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion…

A: It is that point on stress-strain curve, till which stress is linearly varying with strain. As per…

Q: fracture. Determine the following for the two metals (show all calculations and units): a.…

A: Stress vs strain curve is given. BY doing matriculation we can find the unknown.

Q: Q.3 The following data were obtained from the tensile test of Aluminum alloy. The initial diameter…

A: Given data; Gauge length = 2 in Initial diameter = 0.505 in

Q: A steel alloy specimen having a rectangular cross section of dimensions 19.1 mm x 3.1 mm (0.7520 in.…

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Q: Given your understanding of what initiates and controls failure in materials, which of the following…

A: The given question asks which of the given following options increases the failure strength of a…

Q: 1. A cylindrical steel specimen, with an initial diameter of 7mm, has elongated by 40% at the point…

A: Given,  Di = 7 mm  EL = 40% P = 35 kN

Q: (b) (i) A tensile test specimen made from 0.4% C steel has a circular cross section of diameter d mm…

A: Shape of the specimen used is circle of diameter, dGauge length of the specimen = 25 mmLoad applied…

Q: Please answer d,e,f

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Q: The stress-strain diagram for a steel alloy having an original diameter of 0.5 in. and a gage length…

A: We have to determine the value of approximate amount of elastic recovery and the increase in the…

Q: Given your understanding of what initiates and controls failure in materials, which of the following…

A: Designing materials, elements, or structures that can endure periodic or static load requirements is…

Q: A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a…

A:

Q: A steel specimen is tested in tension. The specimen is 25 mm wide by 12.5 mm thick in the test…

A: Area=25×12.5mm2=312.5mm2

Material Properties

Construction in civil engineering demands high strength, durability, and longevity. These targets can be achieved by better design and analysis, along with the correct choice of materials. Different materials have different properties and hence, they respond and performs differently under the various condition of external loadings. It is therefore a critical task of an engineer to select the right material based on the property that the material is supposed to function in real-time. When speaking about the property, there are different categories of material properties like chemical property, physical property, mechanical property, electrical property, magnetic property, thermal property, etc. These material properties form the basis of material selection in various applications.