Question Hel The equation of the least squares regression line is y = 2.0233x-2.3256 and the sum of squared residuals for this line is 0.7907. Answer parts (a)-(d). 7 8 4 12 14 y TUTConsuucra JJ70 CommueTIce ervar avvar uTE mcan vaiue ory AJ. Lower Bound = 7.0 Upper Bound = 8.5 (Round to one decimal place as needed.) (c) Predict the value of y if x= 5. y = 7.8 (Round to one decimal place as needed.) (d) Construct a 95% prediction interval about the value of y if x = 5. Lower Bound Upper Bound (Round to one decimal place as needed.)
Question Hel The equation of the least squares regression line is y = 2.0233x-2.3256 and the sum of squared residuals for this line is 0.7907. Answer parts (a)-(d). 7 8 4 12 14 y TUTConsuucra JJ70 CommueTIce ervar avvar uTE mcan vaiue ory AJ. Lower Bound = 7.0 Upper Bound = 8.5 (Round to one decimal place as needed.) (c) Predict the value of y if x= 5. y = 7.8 (Round to one decimal place as needed.) (d) Construct a 95% prediction interval about the value of y if x = 5. Lower Bound Upper Bound (Round to one decimal place as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The equation of the least squares regression line is y =2.0233x-2.3256 and the sum of squared residuals for this line is 0.7907. Answer parts (a)-(d).
4
5.
7.
8.
4.
12
14
0 OMIIUGI ILG INTLGIVal abVUL UIG IGali VQlUG VLYI
Lower Bound
=7.0
Upper Bound
(Round to one decimal place as needed.)
3D8,5
(c) Predict the value of y if x = 5.
y= 7.8 (Round to one decimal place as needed.)
(d) Construct a 95% prediction interval about the value of y if x = 5.
Lower Bound
%3D
Upper Bound
(Round to one decimal place as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85ca80db-c3c6-42a2-bfa0-51037c0225a3%2F651dc8b5-41fd-4b15-8d79-bb802a70ff1d%2Fo9p1yyl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question Help v
The equation of the least squares regression line is y =2.0233x-2.3256 and the sum of squared residuals for this line is 0.7907. Answer parts (a)-(d).
4
5.
7.
8.
4.
12
14
0 OMIIUGI ILG INTLGIVal abVUL UIG IGali VQlUG VLYI
Lower Bound
=7.0
Upper Bound
(Round to one decimal place as needed.)
3D8,5
(c) Predict the value of y if x = 5.
y= 7.8 (Round to one decimal place as needed.)
(d) Construct a 95% prediction interval about the value of y if x = 5.
Lower Bound
%3D
Upper Bound
(Round to one decimal place as needed.)
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