QuestionFigure Q1 shows the schematic diagram of a moulding press, which is driven by a crank BCrotating anticlockwise at a constant angular velocity (@) of 100 rpm. C and O are fixed pivots andD is the mid-point of link AB. At this instant in time, the crank makes an angle (0) of 80° with thehorizontal as shown. The angle ß is 4° to the vertical and the angle a is 19° to the horizontal asshown.(a) Determine the angular velocities of links OA and AB.(b) Consider the centre of mass of link AB to be at D (as shown in Figure Q1). Determine theabsolute velocity of point D.(c) Determine the angular accelerations of links OA and AB.(d) Determine the absolute acceleration at point D (include its angle to the horizontal 8).A↓aDBC = 50mmOA = 150mmAB = 300mmAD = 150mmFigure Q1. 4-Bar Linkage SystemB

Figure Q1, shows the schematic diagram of a moulding press, which is driven by a crank BC rotating…

Answered: Question Figure Q1 shows the schematic…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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In the image on the right, there is a red gear G1 on the left with a radius of r1 = 2.81cm. Gear G1 is locked to the green gear G2 with a radius of r2 = 0.734cm. Gear G2 then shares the same axle as the blue circular saw G3, which has a radius of r3 known to make a full rotation every T = 0.836s. Using at least 6 significant digits in your calculations, compute the following: V3! 12.8cm. Gear G1 is W1 a) The angular speed wi of gear G1. Remember that angular speed is measured in radians per T3 r2 unit time. G2 b) The rim speed vi of gear G1. Since gears G1 and G2 are locked together, the rim speed of G2 is also v1. G1 G3 c) The angular speed w2 of gear G2. Since gear G2 and saw G3 share the same axle, the angular speed of G3 is also w2. d) The rim speed v3 of saw G3.
Unlike the common V6 engine, Subaru engines contain pistons that are horizontally opposed (see Wikipedia for more info). Luckily for us, this also makes for an interesting dynamics problem! At the instant shown, the crank arm's angular velocity is waB = 2,000 rpm (rotating clockwise) and the angle 0 = 40° with respect to the horizontal. Length of bar AB is r1 = 3 in. and the length of bar BD is r2 = 8 in. a) Clearly define coordinate systems for each link and write transformation arrays for each. b) Compute the velocity of point B in ft/s. Express your answer in rectangular coordinates. [Ans. to Check: 33.66 i– 40.11 j ft/sec] c) Determine the magnitude of the speed of the piston P in ft/s. Note: all answers should be positive since we only want to know the magnitude of the speed, not the direction (the piston can only move in the horizontal direction). [Ans. to Check: 43.6 ft/s] r2 10 B
Another very common basic mechanism is the "four-bar" (the ground is considered one of the bars). The class has designed this demonstration four-bar with dimensions 2.2ft , 4.6ft and 1.0ft . In the position shown, coupler BC is horizontal, rocker CD is vertical and are easily found), and crank AB is rotating at a constant angular (therefore dimensions velocity of 11.8 rad/s Determine the angular velocity of rocker CD. NOTE: Magnitude should be entered here, direction in part 2 of this problem. A LAB WAB B 0A counterclockwise. LAD LBC D LCD
äbö 25 In a mechanism as shown in figure, the crank OA is 100 mm long and rotates in a clockwise direction at a speed of 100 rpm. The link BC is 200 mm long and the link AB is 300 mm long. (a) Draw space diagram and (b) draw the velocity .diagram of point A B 300 mm 30° 100 mm A
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Adjustable Link L m Pivot Pivot Screw 'B' Gripper In the drawing, arm A is being driven back and forth in the direction of the arrows. It is connected to a gripper by way of an adjustable link L, two horizontal bars and two vertical bars. Screw B is a shoulder screw secured to arm A, but allows the horizontal bar to pivot around it. If the shoulder screw B was lowered towards the end of arm A, and the stroke of arm A remained the same, the stroke of the gripper would: Arm 'A' 0 MIMINIA
Given: A shaft rotates about a fixed vertical axis at a constant rate of f, as shown below. A straight bar OA, having a length of L, is pinned to point O on the shaft, with O being on the rotation axis of the shaft. At the instant when 80, bar OA is being raised at a rate of 6 from the horizontal plane, with this rate changing at a rate of . A set of ryz coordinate axes is attached to bar OA with its origin at O. A second set of coordinate axes, XYZ, are fixed to ground. At the instant when = 0, the zyz and XYZ axes are aligned with each other. Find: For the instant when -0°, determine the angular velocity and angular acceleration of har OA. vertical shaft bearing O 8 X bar Use the following parameters in your analysis: f2=5 rad/s, é = 4 rad/s, 6-3 rad/s² and L=2 m.
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What is the chain rule for angular velocity? If we know the angular velocity of the Orbital CCS w.r.t. the Inertial (ECI) CCS, and the angular velocity of the Body CCS w.r.t. the Inertial (ECI) CCS, then write a mathematical expression to find the angular velocity of the Body CCS w.r.t. the Orbital CCS.
a. Which term(s) in this equation is/are eliminated if Point A is stationary? b. Which term(s) in this equation is/are eliminated if Frame A rotates with constant angular velocity? c. Which term(s) in this equation is/are eliminated if Frame A is fixed to a rigid body and Point B is a point on that body? d. From a definition of position vector FB/I = TA/I + TB/A, derive the expression for acceleration below TA/I 144 A TB/1 TB/A B B/1 = A/I +B/A+A/I XTB/A+20A/I XUB/A+WA/IX (WA/IXTB/A)
1. Figure 4.11 shows a kinematic diagram of a mechanism that is driven by moving link Graphically reposition the links of the mechanism as link 2 is displaced 30° counterclockwise. Determine the resulting angular displacement of link 4 and the linear displacement of point. B 3″ AD 4.9" 90° 0 5.3" 3.3" 10.1" D 3.2"

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