Question: Describe or express your simplest technique in solving problems found in task D and E

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Question: Describe or express your simplest technique in solving problems found in task D and E.

Calculate the percent mass of each element of a compound NaHSO3
(Na = 23.0 g/mol; H = 1.008 g/mol; S = 32.0 g/mol; O = 16.0 g/mol). After getting the
percent mass, divide the circle to the computed percentage of each corresponding
element. (Note that the circle is equivalent to 100% as a whole; you can use several
colors to represent each percent mass of the elements.)
%3D
1. Based on your circle, which element has the
biggest mass percent?
2. Which has the smallest mass percent?
Transcribed Image Text:Calculate the percent mass of each element of a compound NaHSO3 (Na = 23.0 g/mol; H = 1.008 g/mol; S = 32.0 g/mol; O = 16.0 g/mol). After getting the percent mass, divide the circle to the computed percentage of each corresponding element. (Note that the circle is equivalent to 100% as a whole; you can use several colors to represent each percent mass of the elements.) %3D 1. Based on your circle, which element has the biggest mass percent? 2. Which has the smallest mass percent?
Calculate the percent by mass of each element in the following compounds:
D
Calculate the mass percent of each element in a compound. Write
Ooleulate the percent by mass of each element in the following compounds:
1. Methane, CH4 (C = 12.01 g/mol; H = 1.008 g/mol)
2 Sodium Nitrate, NaNO3 (Na = 23.0 g/mol; N = 14.0 g/mol; O = 16.0 g/mol)
Transcribed Image Text:Calculate the percent by mass of each element in the following compounds: D Calculate the mass percent of each element in a compound. Write Ooleulate the percent by mass of each element in the following compounds: 1. Methane, CH4 (C = 12.01 g/mol; H = 1.008 g/mol) 2 Sodium Nitrate, NaNO3 (Na = 23.0 g/mol; N = 14.0 g/mol; O = 16.0 g/mol)
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