question d,e,f 12. The figure below shows the velocity of a particle moving along the x-axis from time 0 ≤ t ≤ 10. The position at timet=0 is-3. Use the graph to answer the following question.a) When is the particle moving right?b) When does the body change direction?c) When is the body moving at a constant speed?d) What is the maximum speed?e) When is the particle's acceleration negative?f) What is the particle's position when t = 5?je srit

We are given velocity vs time graph. There are various regions where velocity is changing. We are also given the initial position of the particle. We first find out the maximum speed. We then find the regions where acceleration is negative. We then find the total displacement. We then find the final position.Part d) The speed is magnitude of velocity. We identify from graph when the magnitude reaches maximum. Hence we see that the velocity is reaching maximum magnitude at t=6, Hence maximum speed is 4 units. Part e) The acceleration is negative that is opposite to velocity when the particle is slowing down. From graph, till t=1, the velocity is increasing, hence acceleration is positive. After that velocity becomes constant meaning acceleration is zero. From t=3 to t=6, velocity is decreasing. Meaning the acceleration is negative for t=3 to t=6. After that velocity is again decreasing from t=9 to t=10. The acceleration is negative for t=9 to t=10. Part f) The displacement is area under vt graph. Hence displacement for t=0 to t=5 is s=122+4×2-12×2×1s=5 Hence the final position is s=xf-xixf=5-3xf=2 Hence the final position is 2 .