In a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 15.0 m in diameter. It is found that the pilot blacks out when he is spun at 30.6 rpm (rev/min). At what acceleration (in SI units) does the pilot black out? acceleration: 77.0 m/s² Express this acceleration in terms of a multiple of g. acceleration as a multiple of g: 7.86 8 If you want to decrease the acceleration by 24.0% without changing the diameter of the circle, by what percent must you change the time for the pilot to make one circle? percent of time change: %

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**Assessing Tolerance for High Acceleration in Pilots**

In a controlled laboratory setting designed to test the tolerance for high acceleration, a pilot is swung in a circle with a diameter of 15.0 meters. Through experimentation, it is determined that the pilot experiences a blackout at a rotational speed of 30.6 revolutions per minute (rev/min).

**Determining the Acceleration at Blackout**

The critical question here is: At what acceleration (in SI units) does the pilot black out?

- The recorded acceleration is 77.0 \( \text{m/s}^2 \).

**Expressing Acceleration in Terms of Standard Gravity (g)**

To better understand the level of stress experienced by the pilot, we convert this acceleration into a multiple of the standard acceleration due to gravity (g), which is approximately 9.81 \( \text{m/s}^2 \).

- The acceleration as a multiple of g: 7.86 \( g \).

**Modulating the Test Conditions**

An additional question arises: If you aim to reduce the acceleration by 24.0% without altering the diameter of the circular path, by what percentage must the time taken for the pilot to complete one rotation be changed?

- This question relates to altering the rotational speed to achieve the desired decrease in acceleration. The percentage change required in the time period is yet to be determined and remains open for analysis.
Transcribed Image Text:**Assessing Tolerance for High Acceleration in Pilots** In a controlled laboratory setting designed to test the tolerance for high acceleration, a pilot is swung in a circle with a diameter of 15.0 meters. Through experimentation, it is determined that the pilot experiences a blackout at a rotational speed of 30.6 revolutions per minute (rev/min). **Determining the Acceleration at Blackout** The critical question here is: At what acceleration (in SI units) does the pilot black out? - The recorded acceleration is 77.0 \( \text{m/s}^2 \). **Expressing Acceleration in Terms of Standard Gravity (g)** To better understand the level of stress experienced by the pilot, we convert this acceleration into a multiple of the standard acceleration due to gravity (g), which is approximately 9.81 \( \text{m/s}^2 \). - The acceleration as a multiple of g: 7.86 \( g \). **Modulating the Test Conditions** An additional question arises: If you aim to reduce the acceleration by 24.0% without altering the diameter of the circular path, by what percentage must the time taken for the pilot to complete one rotation be changed? - This question relates to altering the rotational speed to achieve the desired decrease in acceleration. The percentage change required in the time period is yet to be determined and remains open for analysis.
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