Question: Calculate dissociation per mole of NaHSO4 in water. Data Given from this Enthalpy of Neutralization for NaHSO4 experiment: Volume of NaHSO4 = 50 mL & Conc of NaHSO4 = 1.2M Volume of NaOH = 50 mL & Conc of NaOH = 1.5M Mass of combined solution = 100 g Ti of NaHSO4 = 23.4 degrees Celsius and Tf of NaHSO4 = 32 degrees Celsius Moles of NaHSO4 = 1.2M x 50.0E-3 L = 0.060 mol Enthalpy of neutralization per mole of NaHSO4 = -60 KJ/mol

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Question: Calculate dissociation per mole of
NaHSO4 in water.
Data Given from this Enthalpy of Neutralization
for NaHSO4 experiment:
Volume of NaHSO4 = 50 mL & Conc of NaHSO4
1.2M
Volume of NaOH = 50 mL & Conc of NaOH =
1.5M
Mass of combined solution = 100 g
Ti of NaHSO4 = 23.4 degrees Celsius and Tf of
NaHSO4 = 32 degrees Celsius
Moles of NaHSO4 = 1.2M x 50.0E-3 L = 0.060
mol
Enthalpy of neutralization per mole of NaHSO4
= -60 KJ/mol
Transcribed Image Text:Question: Calculate dissociation per mole of NaHSO4 in water. Data Given from this Enthalpy of Neutralization for NaHSO4 experiment: Volume of NaHSO4 = 50 mL & Conc of NaHSO4 1.2M Volume of NaOH = 50 mL & Conc of NaOH = 1.5M Mass of combined solution = 100 g Ti of NaHSO4 = 23.4 degrees Celsius and Tf of NaHSO4 = 32 degrees Celsius Moles of NaHSO4 = 1.2M x 50.0E-3 L = 0.060 mol Enthalpy of neutralization per mole of NaHSO4 = -60 KJ/mol
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