Question 8 of 50ion 82 pointsSave AnswerA normally distributed population with 100 observations has a mean of 10 and unknown standard deviation. A sample of size 25with a sample standard deviation of 4 is randomly drawn from the population. Estimate the population standard deviation o using a95% confidence interval.O A. (1.56; 2.78)O B. (9.76; 30.96)OC (2.44; 7.74)O D. (3.12; 5.56)Question 8 of 50A Moving to the next question prevents changes to this answer.10:1423°C Sunny AD ENG2021/11/29homeendinsprt scdeletef10 111914440backspacelock9600II

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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v Question Completion Status: d. 0.3085 QUESTION 2 EPA fuel economy estimates for automobile models tested recently predicts a mean of 24 and a standard deviation of 6 mpg. Assume that a Normal model applies, N(24, 6). mpg What proportion of automobiles would expect to have gas mileage rates between 10 and 16 mpg? O a. 0.1587 O b. 0.0819 C. 0.0099 O d. 0.0918 QUESTION 3
Assume that a sample is used to estimate a population mean μμ. Find the 90% confidence interval for a sample of size 17 with a mean of 52.8 and a standard deviation of 20.3. Round your answers to two decimal places. ________< μμ < __________
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
acc1
A population of values has an unknown distribution with μ=109.2μ=109.2 and σ=15.3σ=15.3. You intend to draw a random sample of size n=88n=88.What is the mean of the distribution of sample means?μ¯x=μx¯= ____________ (Please enter an exact answer.)What is the standard deviation of the distribution of sample means?σ¯x=σx¯=_____________ (Please report your answer accurate to 2 decimal places.)
Find the left and right chi square values, then give the confidence interval. Sample Variance s 15.99 %3D Confidence Level c = 0.90 and Sample Size n = 13 and x %3D %3D At the 90 % level of confidence the population variance is between and (Round all answers to 3 decimal places)
A pair of dice is rolled 210 times. What is the probability that a total of 7 occurs (a) at least 24 times? (b) between 38 and 48 times inclusive? (c) exactly 35 times? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.
Interstate Speeds It has been reported that the standard deviation of the speeds of drivers on Interstate 75 near Findlay, Ohio, is 8 miles per hour for all vehicles. A driver feels from experience that this is very low. A survey is conducted, and for 29 drivers the standard deviation is 9.1 miles per hour. At =α0.05, is the driver correct? Assume the variable is normally distributed. (a)State the hypotheses and identify the claim with the correct hypothesis.
Find the standard deviation a for the bionomal distribution which has the stated values of n and p.
Breaking Strength of Steel Cable The average breaking strength of a certain brand of steel cable is 2000pounds, with a standard deviation of 100pounds. A sample of 20 cables is selected and tested. Find the sample mean that will cut off the upper 91% of all samples of size 20 taken from the population. Assume the variable is normally distributed. Round intermediate z-value calculations to 2 decimal places and round the final answer to at least 2 decimal places. The sample mean that will cut off the upper 91% of all samples of size 20 is ____ pounds.
Male BMI Female BMI μ H₁ H2 50 x 28.2843 50 25.2598 S 7.119029 4.746586 Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance n level for both parts. What are the null and alternative hypotheses? OA. Ho H₁ =H2 H₁: H1 H2 B. Ho: H1 H2 H₁₁₂ OD. Ho: H₁H H₁₁₂ H₁: H1 H2 The test statistic, t, is 2.5000. (Round to two decimal places as needed.) The P-value is 0.0140. (Round to three decimal places as needed.) State the conclusion for the test. OA. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. B. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. C.…

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